Find 4 consecutive odd numbers such that twice the sum of the least 2 numbers is 40 less than three times the sum of the greates
t two numbers
1 answer:
4 consecutive odd numbers....x, x + 2, x + 4, x + 6
2(x + x + 2) = 3(x + 4 + x + 6) - 40
2(2x + 2) = 3(2x + 10) - 40
4x + 4 = 6x + 30 - 40
4x + 4 = 6x - 10
4x - 6x = -10 - 4
-2x = - 14
x = -14/-2
x = 7
x + 2 = 7 + 2 = 9
x + 4 = 7 + 4 = 11
x + 6 = 7 + 6 = 13
ur numbers are : 7,9,11,13 <==
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