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Jlenok [28]
3 years ago
6

Helen and Stephanie par

Mathematics
1 answer:
Darya [45]3 years ago
4 0

i really really really like birds

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Question 1 of
AnnyKZ [126]

Answer:

5L/2 < 100

Step-by-step explanation:

Let's get started!

Let :

⇒ Length = L

⇒ Width = L/4

It mentions the perimeter must be less than 100 inches.

Perimeter Formula :

<u><em>Perimeter (Rectangle) = 2(Length + Width)</em></u>

Then, the inequality formed will be :

⇒ 2 (L + L/4) < 100

⇒ 2 (5L/4) < 100

⇒ 10L/4 < 100

⇒ 5L/2 < 100

3 0
2 years ago
Read 2 more answers
Consider the system of equations.
anzhelika [568]

Answer: You can multiply the top equation by -1 to eliminate the x variable.

And the solution is (2,4/3)  in case you need it.

Step-by-step explanation:

2x + 3y = 8

2x + 6y = 12

If you multiply the upper equation or down equation by one, you will be able to eliminate the x variable.

-1( 2x + 3y) = -1(8)     New equation:   -2x -3y  = -8.

Add the new equation you got  by multiplying the top equation by -1 to the bottom equation.

Add them:     -2x -3y = -8

                      2x + 6y = 12  

                               3y = 4  

                              y = 4/3

You can now input the value for y into the one of the equations and solve for x.

-2x - 3(4/3) = -8

-2x -4 = -8  

     +4     +4

-2x = -4

x = 2

8 0
3 years ago
What's bigger 3/4 or 9/12
pashok25 [27]
Change the common denominator so 3/4 ---> 9/12 
3/4 and 9/12 are equal

Hope this helps!!!
3 0
3 years ago
Read 2 more answers
Which is the side length of a cube with a volume of 2744 cm3?<br><br> Please help
Elis [28]
\sf~V=a^3

Plug in what we know:

\sf2744=a^3

Find the cube root of both sides:

\sf~a=\sqrt[3]{2744}

Simplify:

\sf~a=\boxed{\sf14}
3 0
3 years ago
Read 2 more answers
Which of the following values of y will result in a true statement when substituted into the given equation?
strojnjashka [21]

Answer:

A. -0.8

Step-by-step explanation:

non of the other answers will work because they are positive.

5 0
2 years ago
Read 2 more answers
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