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kherson [118]
3 years ago
10

Which value for x makes the open sentence true. 4•3 -2x < X2 -2

Mathematics
2 answers:
Angelina_Jolie [31]3 years ago
4 0
First subtract 12 from both sides, then subtract 2x from both sides, multiply both sides by -1, then divide by 4.  

x > 3.5
bulgar [2K]3 years ago
3 0
From using order of operations I got x < -7
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Rob is saving to buy a new MP3 player. For every $14 he earns babysitting, he saves $6. On
abruzzese [7]

Answer:

<em>Rob has saved </em><em>$24</em><em>.</em>

Step-by-step explanation:

The first thing I noticed was that Rob only saved some of the money he earned. That means only x% only gets saved. To find x, I simply divided 6 by 14 and got 0.42857142857. Then to find the amount he saved from earning $56, I multiplied that number with 56 and got 24.

7 0
3 years ago
The volume of a cup would most likely be measured in
butalik [34]
Most likely in millilitres, kilolitres is too large for a small cup, and the other measurements are for mass
8 0
3 years ago
Help me solve this please
damaskus [11]

1) A quadratic will have no real roots when its discriminant is negative


0 = ax^2 + bx + c = x^2 + 2k x + (4k-3)


d = b^2 - 4ac =  (2k)^2 - 4(1)(4k-3) = 4k^2 - 16k + 12 < 0


Dividing by 4,


k^2 - 4 k + 3 < 0 \quad\checkmark


We have a positive coefficient on k^2 so this parabola is a CUP (concave up positive) so has a minimum at the vertex. If the vertex y value is less than zero, the inequality will be true in the range between the zeros.


(k-3)(k-1)


That's true for


1 < k < 3


2) We look for the meet of the line and the parabola:


2x + k + 2 = 2x^2 + (k+2)x + 8


0 = 2x^2 + kx + (6-k)


For two intersections we need a positive discriminant:


k^2 - 4(6-k)(2) > 0


k^2 + 8k - 48 > 0


(k+12)(k-4) > 0


That's means two negative or two positive, so


k < 12 or k > 4


6 0
3 years ago
Ashton needs a total of $1.50 in quarter for a coin
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Six Quarters Is How Many He Needs
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3 years ago
Read 2 more answers
Which of these ordered pairs is a solution to the linear inequality 2y-3x≤-10?
Alexandra [31]
2y-3x≤-10
just insert your points into it:

a: 2*2-3*-4<=-10?
4+12<=-10? no

b: 2*3-3*1<=-10?
6-3<=-10? no

c: 2*-4-3*2<=-10?
-8-6<=-10?
yes c is a solution: -14<=-10

d: 2*4-3*4<=-10?
8-12<=-10? no
4 0
3 years ago
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