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3 years ago

After taking the first exam, 15 of the students dropped the class. The value 15 describes _____ .

Mathematics

1 answer:

Bess [88]3 years ago

3 0

Answer:

After taking the first exam, 15 of the students dropped the class. The value 15 describes a characteristic of a population - first choice.

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Can you help me with this

Karo-lina-s [1.5K]

Answer

38°

Step-by-step explanation:

52+90+x=180

180-52-90=x

x=38

3 0

2 years ago

Read 2 more answers

What is the Bill of Rights?

defon

Answer:

The list of laws that people of the United Stated needed to follow

Step-by-step explanation:

7 0

2 years ago

AWARDING EXTRA POINTSWhat is the distance between point A (-3, -2) and Point B (4, -7)?

kenny6666 [7]

Answer:

Hi there!

Your answer is:

8.6 units

Step-by-step explanation:

The distance formula is

√ ( (x2-x1)^2 + (y2-y1)^2 )

In your points:

A (-3, -2)

-3 is x1

-2 is y1

B (4, -7)

4 is x2

-7 is y2

Plug in to distance formula

√ ( 4-( -3))^2 + ( -7 - (-2))^2

√ (4+3)^2 + (-7+2)^2

√ (7^2) + ( -5)^2

√ 49 + 25

√ 74

This equals roughly 8.6 units!

4 0

3 years ago

Find the zeros of f(x)=-3x^3+6x+5.

Tasya [4]

Answer:

x = 1.723

Step-by-step explanation:

The zeros of a function f(x) are the points where the function crosses the x-axis. At these points, the function will have a value of zero, that is;

f(x) = 0

We simply graph the function and determine the points where it crosses the x-axis. From the attachment, f(x) crosses the x-axis at;

x = 1.723

8 0

3 years ago

Read 2 more answers

An 8.0 kg block is moving at 3.2 m/s. A net force of 10 N is constantly applied on the block in the direction of its movement, u

Softa [21]

Answer:

5.02 m/s

Step-by-step explanation:

We are given that

Mass of block,m=8 kg

Initial velocity,u=3.2 m/s

Net force ,F=10 N

Distance,s=6 m

We have to find the approximate final velocity of the block.

We know that $a=\frac{F}{m}$

Using the formula

$a=\frac{10}{8}=\frac{5}{4} m/s^2$

We know that

$v=\sqrt{u^2+2as}$

Using the formula

$v=\sqrt{(3.2)^2+2\times \frac{5}{4}\times 6}$

$v=5.02 m/s$

8 0

2 years ago