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3 years ago

3 2/5 time 5. Show work

Mathematics

1 answer:

xenn [34]3 years ago

8 0

let's firstly convert the mixed fraction to improper fraction and then multiply.

$\bf \stackrel{mixed}{3\frac{2}{5}}\implies \cfrac{3\cdot 5+2}{5}\implies \stackrel{improper}{\cfrac{17}{5}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{17}{~~\begin{matrix} 5 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\cdot ~~\begin{matrix} 5 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~\implies 17$

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What type of relationship does a correlation coefficient of r = 0.45 indicate?

WINSTONCH [101]

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Strong positive correlation

Step-by-step explanation:

The closer the value of ρ is to +1, the stronger the linear relationship. For example, suppose the value of oil prices are directly related to the prices of airplane tickets, with a correlation coefficient of +0.8.

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3 years ago

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2 years ago

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ValentinkaMS [17]

<u>Answer</u>

A) 7.3 in.

Explanation

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3 years ago

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3 years ago

The following lists the joint probabilities associated with smoking and lung disease among 60-to-65 year-old men. Has Lung Disea

Anna71 [15]

Answer:

4.11% probability that he has lung disease given that he does not smoke

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Does not smoke

Event B: Lung disease

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This means that $P(A \cap B) = 0.03$

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This means that $P(A) = 0.03 + 0.7 = 0.73$

What is the probability of the following event: He has lung disease given that he does not smoke?

$P(B|A) = \frac{0.03}{0.73} = 0.0411$

4.11% probability that he has lung disease given that he does not smoke

5 0

3 years ago