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3 years ago

Brace ran a race that was 2.5 miles long how long was the race to the nearest hundred feet

1 answer:

4 0

Well its like this 1 mile = 5280 feet
so just write it like 2.5 x 5280= 13200
^ ^ ^
miles feet total feet

so your final answer is: he ran 13200 feet

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Solve the equation and check your solution. (If all real numbers are solutions, enter REALS. If there is no solution, enter NO S

shepuryov [24]

Answer:

y=6/5 or 1 1/5

Step-by-step explanation:

combine like terms

5y+1= 10y-5

subtract 5y from both sides

1=5y-5

add 5 to both sides

6=5y

divide by 5 on both sides

6/5=y

5 0

3 years ago

Joe wants to rent a scooter for a day. It will cost the daily fee of $15 plus $0.25 per mile driven. Let m = the number of miles

Artyom0805 [142]

Answer:

What you´re going to do, is 0.25 x 20, and that is about 5.00. Then you do 15 + 5 and you get 20 dollars for 20 miles. M = $20

Step-by-step explanation:

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2 years ago

375 x 22<br><br> What is the answer and how do we get it

Novay_Z [31]

Answer:

375x22= 8,250

Step-by-step explanation:

use a calculator!

5 0

1 year ago

the animal shelter has space for 800 animals there were already 468 animals at the shelter after a storm a hundred ninety two mo

Anna007 [38]

Answer:

It is reasonable.

Step-by-step explanation:

If you add 468 (amount of animals already there) and add how ever many more coming (192) then you'll get 680. If you add 100 more that will only be 780 animals.

6 0

3 years ago

Explain how to find each root, with its multiplicity, for the polynomial y=x^5-27x^2.

Nuetrik [128]

The roots of $y = x^{5}-27\cdot x^{2}$ are 0 (multiplicity 2), -3 (multiplicity 1), $-\frac{3}{2}+i\,\frac{3\sqrt{3}}{2}$ (multiplicity 1) and $-\frac{3}{2}-i\,\frac{3\sqrt{3}}{2}$ (multiplicity 1).

The characteristics of the polynomial can be derived from algebraic techniques. Roots and multiplicity can be found by <em>factoring</em> the polynomial. The multiplicity is represented by a power binomial of the form:

$(x-r_{i})^{m},\,m \le n$ (1)

Where $n$ is the grade of the polynomial.

Now we proceed to factor the formula:

$y = x^{5}-27\cdot x^{2}$

$y = x^{2}\cdot (x^{3}-27)$

$y = x^{2}\cdot (x^{2}+3\cdot x +9)\cdot (x-3)$

Please notice that $x^{2}+3\cdot x + 9$ have two complex roots.

$y = x^{2}\cdot \left(x+\frac{3}{2}-i\,\frac{3\sqrt{3}}{2} \right)\cdot \left(x+\frac{3}{2}+i\,\frac{3\sqrt{3}}{3} \right)\cdot (x-3)$

The roots of $y = x^{5}-27\cdot x^{2}$ are 0 (multiplicity 2), -3 (multiplicity 1), $-\frac{3}{2}+i\,\frac{3\sqrt{3}}{2}$ (multiplicity 1) and $-\frac{3}{2}-i\,\frac{3\sqrt{3}}{2}$ (multiplicity 1).

We kindly invite to see this question on polynomials: brainly.com/question/1218505

7 0

2 years ago