X + 5 < 533 Subtract 5 from each side
- 5 -5
-----------------
x < 528
Alright, so we know that the race is 5 kilometers, so the equation will be 5-<some value>= <distance from finish line>. We also know that the student runs a kilometer every three minutes, so 3x=1km . Multiplying both sides by 5, we get 15y=5km (y being the number to make the equation make sense, or the slope). When the student has run 5km, the distance from the student to the finish line should be 0, so we get that 5-5=0, and plugging 15y in for 5 we get 5-15y=0. For 15x to equal 5, 3y=1 and y=1/3. Therefore, we plug that in for y, getting 5-15(1/3)=0. However, we have to make it for all times! Since 15 represents the minutes, we make that x, and since 0 represents the distance remaining, we make that the distance remaining, making it 5-(1/3)x=distance left. You can also think of y as the slope in y=mx+b - it stays constant that way.
Imagine the graph of f(x)=|x|. This can only output positive values (
).
Then f(x)=|x|+2 is the same graph shifted upwards by two units meaning it can only output values bigger or equal to than 2. So the range is
Answer:
depends
Step-by-step explanation:
