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3 years ago

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Serena estimates that she can paint 60 square feet of wall space every half-hour. Write an equation for the relationship with ti

me in hours as the independent variable x and the square footage she can paint as the dependent variable y. Can she paint 400 square feet in 3.5 hrs

2 answers:

juin [17]3 years ago

7 0

Answer:

0.5

Step-by-step explanation:

Katarina [22]3 years ago

6 0

Answer:

So, the relationship with i hours as the indecent variables would be

Serena can't paint 400 square feet of wall space of wall space in 3.5 hours.

Step-by-step explanation:

Since we have given that

Area that she can paint = 60 square feet

Time taken = half hour = 30 minutes = 0.5 hours

Using "Unitary method, we get that

In 0.5 hours, she can paint = 60 square feet

In 1 hour, she can paint =

In i hours, she can paint =

Let the total area she can paint be 'y'.

So, the relationship with i hours as the indecent variables would be

Now, Can Serena paint 400 square feet of wall space i. 3.5 hours

We put y = 400 and i = 3.5 hours to check whether it is equal or not.

Hence, Serena can't paint 400 square feet of wall space of wall space in 3.5 hours.

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The liquid base of an ice cream has an initial temperature of 86°C before it is placed in a freezer with a constant temperature

Karolina [17]

The temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

From Newton's law of cooling, we have that

$T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}$

Where

$(t) = \ time$

$T_{(t)} = \ the \ temperature \ of \ the \ body \ at \ time \ (t)$

$T_{s} = Surrounding \ temperature$

$T_{0} = Initial \ temperature \ of \ the \ body$

$k = constant$

From the question,

$T_{0} = 86 ^{o}C$

$T_{s} = -20 ^{o}C$

∴ $T_{0} - T_{s} = 86^{o}C - -20^{o}C = 86^{o}C +20^{o}C$

$T_{0} - T_{s} = 106^{o} C$

Therefore, the equation $T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}$ becomes

$T_{(t)}=-20+106 e^{kt}$

Also, from the question

After 1 hour, the temperature of the ice-cream base has decreased to 58°C.

That is,

At time $t = 1 \ hour$ , $T_{(t)} = 58^{o}C$

Then, we can write that

$T_{(1)}=58 = -20+106 e^{k(1)}$

Then, we get

$58 = -20+106 e^{k(1)}$

Now, solve for $k$

First collect like terms

$58 +20 = 106 e^{k}$

$78 =106 e^{k}$

Then,

$e^{k} = \frac{78}{106}$

$e^{k} = 0.735849$

Now, take the natural log of both sides

$ln(e^{k}) =ln( 0.735849)$

$k = -0.30673$

This is the value of the constant $k$

Now, for the temperature of the ice cream 2 hours after it was placed in the freezer, that is, at $t = 2 \ hours$

From

$T_{(t)}=-20+106 e^{kt}$

Then

$T_{(2)}=-20+106 e^{(-0.30673 \times 2)}$

$T_{(2)}=-20+106 e^{-0.61346}$

$T_{(2)}=-20+106\times 0.5414741237$

$T_{(2)}=-20+57.396257$

$T_{(2)}=37.396257 \ ^{o}C$

$T_{(2)} \approxeq 37.40 \ ^{o}C$

Hence, the temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

Learn more here: brainly.com/question/11689670

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What number is ten thousand less than 842719

almond37 [142]

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4 0

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What is the length of the arc when the degree measure is 60° and the radius is 7?

shepuryov [24]

Inscribed angle =1/2 arc

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3 years ago

Mieko said that the difference between the longest rose and the shortest rose is 1 inch. Is she correct?

erastova [34]

Answer:

Mieko is correct

Step-by-step explanation:

Given

See attachment for complete question

Required

The length difference

Lengths with dot(s) means, there is at least 1 rose flower of that length.

So, from the attachment, we have:

$Longest = 14.0$

$Shortest = 13.0$

The difference (d) is:

$d = Longest - Shortest$

This gives:

$d = 14.0 - 13.0$

$d = 1\ in$

<em>Hence, Mieko is correct</em>

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Answer:

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Step-by-step explanation:

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