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Orlov [11]
3 years ago
9

PLS HELP it's DUE TODAY

Mathematics
2 answers:
TiliK225 [7]3 years ago
7 0

Answer:

C) \frac{1 yd}{36 in} =\frac{7 yd}{252}

Explanation:

A) 1.64935065 = 1.00565611

B) 1 = 1.13513514

C) 1 = 1

D) 1.00025607 = 1.00463164

Only C is true, so the answer is C

charle [14.2K]3 years ago
6 0

Answer:

Third answer

Step-by-step explanation:

1 x 7 = 7

36 x 7 = 252

You might be interested in
Given the equation -5x+2y=-10 what is the equation of the line perpendicular to the line?
meriva

Answer:

The equation of the perpendicular line would be y = -2/5x - 1

Step-by-step explanation:

In order to find this line, we must first find the slope of the original line. We do this by solving for y.

-5x + 2y = -10

2y = 5x - 10

y = 5/2x - 5

This shows us a slope of 5/2. TO find the perpendicular slope, we use the opposite and reciprocal. This means we negative 5/2 to get -5/2 and then we flip it to get -2/5. Now that we have this, we can use the slope and the point in point-slope form to get the equation.

y - y1 = m(x - x1)

y - 1 = -2/5(x + 5)

y - 1 = -2/5x - 2

y = -2/5x - 1

4 0
3 years ago
Caroline bought 20 shares of stock at 10 1/2, and after 10 months the value of the stocks was 11 1/4. If Caroline were to sell a
mojhsa [17]

11.25 - 10.5 = 0.75

Knowing that this is the profit she makes with one share, so:

20 * 0.75 = 15

Caroline made $15 profit.

7 0
3 years ago
The local branch of the Internal Revenue Service spent an average of 21 minutes helping each of 10 people prepare their tax retu
AURORKA [14]

Answer:

The confidence Interval is [- 0.7053  10.4521]

a: The  hypotheses  are

H0: μ1=μ2    against the claim Ha :μ1≠μ2

b. The critical value for t∝/2 for 17 d.f  t > 2.508 and  t < -2.111

c. t= -2.8422

d. The calculated value of t= -2.8422 is less than t < -2.11 the critical value therefore we reject H0 and conclude there is a difference between the two means.

Step-by-step explanation:

When the standard deviations are not the same then the confidence intervals for mean differences are calculated as

(x1`-x2`)- t∝/2 √s1²/n1 + s2²/n2 < u1-u2 < (x1`-x2`)+ t∝/2 √s1²/n1 + s2²/n2

x1`= 21        x2`= 27

n1=  10       n2= 14

s1= 5.6       s2= 4.3

The degrees of freedom is calculated using

υ = [s₁²/n1 + s₂²/n2]²/ (s₁²/n1 )²/ n1-1 + (s₂²/n2)²/n2-1

= 17

The t∝/2 for 17 d.f = 2.11

Putting the values

(x1`-x2`)- t∝/2 √s1²/n1 + s2²/n2 < u1-u2 < (x1`-x2`)+ t∝/2 √s1²/n1 + s2²/n2

(21-27) - 2.11√5.6²/10+ 4.3²/14 < u1-u2 <(21-27)  +2.11√5.6²/10+4.3²/14

6- 2.11*2.111 < u1-u2 <  ( 6 )  +2.11*2.111

6- 4.4521 < u1-u2 <  ( 6 )  +5.294

- 1.5479 < u1-u2 <  10.4521

The confidence Interval is [- 0.7053  10.4521]

a: The  hypotheses  are

H0: μ1=μ2    against the claim Ha :μ1≠μ2

The claim is that there is a difference in the average time spent by the two services

b. The critical value for t∝/2 for 17 d.f  t > 2.508 and  t < -2.111

The degrees of freedom is calculated using

υ = [s₁²/n1 + s₂²/n2]²/ (s₁²/n1 )²/ n1-1 + (s₂²/n2)²/n2-1

= 17

c. The test statistic is

t= (x1`-x2`)  /√s1²/n1 + s2²/n2

t= (21-27)  /√5.6²/10+ 4.3²/14

t= -6/2.111

t= -2.8422

d. The calculated value of t= -2.8422 is less than t < -2.11 the critical value therefore we reject H0 and conclude there is a difference between the two means.

5 0
3 years ago
AYUDAAA porfavorrrr primera urna 6 bolas verdes y 3 rojas segunda urna 3 verdes, 3 blancas y 3 rojas tercera urna 6 verdes, 1 bl
marin [14]

We have the following information:

first urn: 6 green balls and 3 red ones

total: 6 + 3 = 9

second urn: 3 green, 3 white and 3 red

total: 3 + 3 + 3 = 9

third urn: 6 green, 1 white and 2 red

total: 6 + 1 + 2 = 9

a) A green ball is more likely to be obtained, since there are more green balls than red balls, which makes the probability higher.

b) probability of drawing a green, red and white ball.

first urn:

green = 6/9 = 66.66%

red = 3/9 = 33.33%

white = 0/9 = 0%

second urn:

green = 3/9 = 33.33%

red = 3/9 = 33.33%

white = 3/9 = 33.33%

third urn:

green = 6/9 = 66.66%

red = 2/9 = 22.22%

white = 1/9 = 11.11%

c) it would be chosen where the probability of drawing green would be the highest, which means that it would be possible both in the first and in the third ballot box, the probability is equal 66.66%

d) without a green ball, the third ballot box would look like this:

5 green balls, 2 red balls and 1 white ball, with a total of 8.

The probability of drawing would be:

green = 5/8 = 62.5%

red = 2/8 = 25%

white = 1/8 = 12.5%

7 0
3 years ago
Which of the following could be the perimeter of a rectangle with an area of 16 square inches?
Butoxors [25]

no doubt it's 16 inches

8 0
3 years ago
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