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Orlov [11]
3 years ago
9

PLS HELP it's DUE TODAY

Mathematics
2 answers:
TiliK225 [7]3 years ago
7 0

Answer:

C) \frac{1 yd}{36 in} =\frac{7 yd}{252}

Explanation:

A) 1.64935065 = 1.00565611

B) 1 = 1.13513514

C) 1 = 1

D) 1.00025607 = 1.00463164

Only C is true, so the answer is C

charle [14.2K]3 years ago
6 0

Answer:

Third answer

Step-by-step explanation:

1 x 7 = 7

36 x 7 = 252

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Compute delta y/delta x for the interval [2,5], where y = 4x - 9.
Kamila [148]
We have to compute: Δ y / Δ x.
The interval is [ 2, 5 ] and y = 4 x - 9.
y 1 = 4 · 2 - 9 = 8 - 9 = - 1
y 2 = 4 · 5 - 9 = 20 - 9 = 11
Δ y / Δ x = ( y 2 - y 1 ) / ( x 2 - x 1 ) =
= ( 11 - ( - 1 ) ) / ( 5 - 2 ) = ( 11 + 1 ) / 3 = 12 / 3 = 4
Answer:
Δ y / Δ x = 4

3 0
3 years ago
The following stem-and-leaf plot represents the scores earned by Mr. Roberts's class on their most recent science test.
Alinara [238K]
First we need to count the total number scores. This can be done from the stem and leaf plot. The total number of scores are 19. The total number of values is odd, so the median position will be:

\frac{19+1}{2}=10th

Thus the 10th score is the median score for the class of Mr. Robert. The 10th score from the stem and leaf plot is 81.

Thus 81 is the median score of Mr. Robert's Class. 
5 0
4 years ago
Read 2 more answers
At Jefferson Middle School, 3/5 of the students play a sport. Of those students, 1/3 play soccer. What equation can be used to f
yaroslaw [1]

Answer:

a

Step-by-step explanation:

I think that right so let me know if It is right

7 0
3 years ago
In AABC, AB = 2 and AC = 11. Find m2C to the nearest degree.<br>help please​
AlexFokin [52]

Answer:

10

Step-by-step explanation:

<h3>Calculating BC</h3><h3>BC = √2^2 + 11^2 </h3><h3>BC = √ 4+121</h3><h3>BC = √ 125 = 11.18</h3>

to find measure of angle C use sinerule

<h3>sinC/C = sinA/A</h3><h3>sinC/2= Sin90/11.18</h3><h3>SinC = 2×1/11.18</h3>

<h3>sinC = 2/11.18</h3><h3>sinC = (0.1788)</h3><h3>C = sin^-1(0.1788)</h3>

<h3>C = 10.305</h3><h3>C = 10 (approximately)</h3>
4 0
2 years ago
The mean number of hours of study time per week for a sample of 562 students is 23. If the margin of error for the population me
Vadim26 [7]

Answer:

The 98% confidence interval for the mean number of hours of study time per week for all students is (20.9, 25.1).

Step-by-step explanation:

Confidence interval:

Sample mean plus/minus the margin of error.

In this question:

Mean of 23.

Margin of error 2.1.

Then

23 - 2.1 = 20.9

23 + 2.1 = 25.1

The 98% confidence interval for the mean number of hours of study time per week for all students is (20.9, 25.1).

3 0
2 years ago
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