Write A real world problem that can be solved by the equation y + 8 = 20.Then solve your problem.

1 answer:

7 0

Brad and Bella have 20 carrots. Brad has 8 carrots, how many carrots does Bella have?

y + 8 = 20

Subtract 8 from both sides.

y = 12

Bella has 12 carrots.

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Solve the inequality 2x>30+5/4x

insens350 [35]

Answer:

Step-by-step explanation:

$2x > 30+\frac{5}{4x} \\2x-\frac{5}{4x} > 30\\\frac{8x^2-5}{4x} > 30\\case~1\\if~x > 0\\8x^2-5 > 120x\\8x^2-120x > 5\\x^2-15x > \frac{5}{8} \\adding~(-\frac{15}{2} )^2~to~both~sides\\(x-\frac{15}{2} )^2 > \frac{5}{8}+\frac{225}{4} \\(x-\frac{15}{2} )^2 > \frac{455}{8} \\x-\frac{15}{2} < -\sqrt{\frac{455}{8} } \\x < \frac{15}{2}-\sqrt{\frac{455}{8} } \\or~x < 0\\rejected~as~x > 0$

$x-\frac{15}{2} > \sqrt{\frac{455}{8} } \\x > \frac{15}{2} +\sqrt{\frac{455}{8} }$

case~2

$if~x < 0\\8x^2-5 < 120x\\8x^2-120x < 5\\x^2-15x < \frac{5}{8} \\adding~(-\frac{15}{2} )^2\\(x-\frac{15}{2} )^2 < \frac{5}{8} +(-\frac{15}{2} )^2\\|x-\frac{15}{2} | < \frac{5+450}{8} \\-\sqrt{\frac{455}{8} } < x-\frac{15}{2} < \sqrt{\frac{455}{8} } \\\frac{15}{2} -\sqrt{\frac{455}{8} } < x < \frac{15}{2} +\sqrt{\frac{455}{8} } \\but~x < 0\\7.5-\sqrt{\frac{455}{8} } < x < 0$

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The table below shows the combination of a dry prepackaged mix and water to make concrete. The mix says for every 1 gallon of wa

egoroff_w [7]

Let's assign a variable x to the number of multiples for each pound of dry mix and water. With that being the said, the question for finding the total pounds would be:

Total pounds = x*Pounds of dry mix + x*Pounds of water
Total pounds = 60x + 8x = 68x = 14 + 1/6 = 85/6
x = 85/6 / 68
x = 5/24

Thus, the pounds of dry mix is 60*5/24 = 25/2 lbs, while the pounds of water is 8*5/24 = 5/3 pounds.

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