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noname [10]
3 years ago
9

A carpenter leans a 20-foot ladder against a building so that an angle of 60° is formed between the ladder and the ground. How m

any feet away from the
building is the bottom of the ladder?
O 10/3ft
O 20 ft
O 20V2 ft
O 10 ft
Mathematics
2 answers:
iogann1982 [59]3 years ago
8 0

Answer:

The foot of the ladder is

10

feet away from the base of the wall.

Step-by-step explanation:

Ivanshal [37]3 years ago
3 0
10 is the answer hop it is right
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zimovet [89]
15% = 15/100 = 0,15

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Please help logarithms!
nlexa [21]

Given:

\log_34\approx 1.262

\log_37\approx 1.771

To find:

The value of \log_3\left(\dfrac{4}{49}\right).

Solution:

We have,

\log_34\approx 1.262

\log_37\approx 1.771

Using properties of log, we get

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_349      \left[\because \log_a\dfrac{m}{n}=\log_am-\log_an\right]

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_37^2      

\log_3\left(\dfrac{4}{49}\right)=\log_34-2\log_37          [\log x^n=n\log x]

Substitute \log_34\approx 1.262 and \log_37\approx 1.771.

\log_3\left(\dfrac{4}{49}\right)=1.262-2(1.771)

\log_3\left(\dfrac{4}{49}\right)=1.262-3.542

\log_3\left(\dfrac{4}{49}\right)=-2.28

Therefore, the value of \log_3\left(\dfrac{4}{49}\right) is -2.28.

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3 years ago
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THEOREM:

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ANSWER:

[3] By pythagorean theorem,

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  • x = 16.64 rounded.

[4] By pythagorean theorem,

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[5] By pythagorean theorem,

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  • 4x² = 441 – 158.76
  • 4x² = 284.24
  • x² = 284.24/4 = 70.56
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[6] By tangent property,

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Answer:

See Step by step explanation

Step-by-step explanation:

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2 years ago
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