All categories

3 years ago

What is the equation of the line in standard form? 3x−y=−6 3x + y = 6 x + 6y = 9 x−6y=−9

Mathematics

1 answer:

lisabon 2012 [21]3 years ago

8 0

The standard form: Ax + By = C

3x - y = -6 YES - A = 3, B = -1, C = -6

3x + y = 6 YES - A = 3, B = 1, C = 6

x + 6y = 9 YES - A = 1, B = 6, C = 9

x - 6y = -9 YES - A = 1, B = -6, C = -9

You might be interested in

Is 3 x 1/2 greater than 5?

Kryger [21]

No it is not greater than 5

When ever you are multiply a number by 1/2 you are halving the number. So in the us case 3 x 1/2 is 1.5.

And 1.5 is not greater than 5

So the answer is no

Can you please mark brainleist

3 0

3 years ago

Can someone write the slope-intercept form of the graph below

abruzzese [7]

Answer:

y = -2x + 2 i think

Step-by-step explanation:

5 0

3 years ago

Leslie and Daniel plan to put an above-ground pool in the backyard of their new home. The backyard is rectangular, 30 feet by 50

Brut [27]

1047.84ft² is not covered by the pool.
Find the area of the yard covered by pull using the area of a circle formula (the height is irrelevant in this case). If the diameter of the pool is 24 feet, its radius is 12 (half of the diameter)

A = 3.14r^2
A =3.14(144)
A = 452.16 ft²

Subtract the area of the pool from the area of the yard to get the area of the yard that is not covered by the pool. If the dimensions of the yard are 30ft by 50ft, you multiply them to get the area: 1500ft²

Total yard area: 1,500ft²
Area of yard without pool: 1,500ft² - 452.16ft² = 1047.84ft²

4 0

4 years ago

Jason has $90 to spend. He wants to purchase a bag for $30, one eraser for $10, and three pencils. Each pencil cost the same pri

svetlana [45]

$16.67 would be the price of each pencil. You divide 50 by 3 and get 16.6 repeating so you round it up to 16.67

7 0

3 years ago

It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute

Molodets [167]

Answer:

10.38% probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes.

99.55% probability that the mean number of minutes of daily activity of the 6 lean people exceeds 410 minutes

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mildly obese

Normally distributed with mean 375 minutes and standard deviation 68 minutes. So $\mu = 375, \sigma = 68$

What is the probability (±0.0001) that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes?

So $n = 6, s = \frac{68}{\sqrt{6}} = 27.76$

This probability is 1 subtracted by the pvalue of Z when X = 410.

$Z = \frac{X - \mu}{s}$

$Z = \frac{410 - 375}{27.76}$

$Z = 1.26$

$Z = 1.26$ has a pvalue of 0.8962.

So there is a 1-0.8962 = 0.1038 = 10.38% probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes.

Lean

Normally distributed with mean 522 minutes and standard deviation 106 minutes. So $\mu = 522, \sigma = 106$