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3 years ago

8

Why is the product of two rational numbers always rational?

1 answer:

ludmilkaskok [199]3 years ago

5 0

Answer:

all three blanks are integers

Step-by-step explanation:

Let a/b and c/d represent two rational numbers. This means a, b, c, and d are _integers____, and b and d are not 0. The product of the numbers ac/bd, where bd is not 0. Both ac and bd are integers_____, and bd is not 0. Because ac/bd is the ratio of two integers_____, the product is a rational number.

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3 years ago

Scott wants to cover his patio with concrete pavers. If the patio is shaped like a trapezoid whose bases are 11 feet and 13 feet

GenaCL600 [577]

<u><em>Answer:</em></u>

Scott will need 168 ft² of pavers to cover his patio

<u><em>Explanation:</em></u>

Scott wants to cover a trapezoid-shaped patio

<u>This means that:</u>

To get the number of square feet of pavers he'll need, we need to get the area of his patio

<u>Area of trapezium id calculated as follows:</u>

$Area = \frac{base_{1}+base_{2}}{2} * height$

<u>We are given that:</u>

base₁ = 11 ft

base₂ = 13 ft

height = 14 ft

<u>We now substitute with the givens to get the area as follows:</u>

$Area = \frac{11+13}{2} * 14 = 168ft^2$

<u>This means that:</u>

Scott will need 168 ft² of pavers to cover his patio

Hope this helps :)

5 0

3 years ago

Rounded to the nearest hundredth, what is the positive solution to the quadratic equation 0 = 2x2 + 3x – 8? Quadratic formula: x

Lynna [10]

ANSWER

1.39

EXPLANATION

The given quadratic equation is

$0 = 2 {x}^{2} + 3x - 8$

This is the same as,

$2 {x}^{2} + 3x - 8 = 0$

Comparing to

$a {x}^{2} + bx + c = 0$

We have

a=2, b=3,c=-8

Using the quadratic formula, the solution is given by:

$x = \frac{ - b \pm \: \sqrt{ {b}^{2} - 4ac} }{2a}$

We substitute the values to get,

$x = \frac{ - 3\pm \: \sqrt{ {3}^{2} - 4(2)( - 8)} }{2(2)}$

$x = \frac{ - 3\pm \: \sqrt{ 73} }{4}$

The positive root is

$x = \frac{ - 3 + \: \sqrt{ 73} }{4} = 1.39$

to the nearest hundredth.

4 0

3 years ago

Read 2 more answers