To answer this you will use the formula for finding area of a parallelogram.
A = bh
3 inches x 2 inches
A = 6 square inches per piece of paper
6 square inches x 15 = 90 square inches
90 in.² of paper is used to make 15 pieces.
Supplementary angles , when added, = 180
complimentary angles, when added, = 90
< AQC + < GQC = 180.....supplementary
< BQD + < DQE = 90.......complimentary
< CQE + < EQF = 90.......complimentary
< GQF , < FQE.....neither
< BQC + < DQC = 90....complimentary
< W and < X are supplementary...
if < W = 37, then < X = (180 - 37) = 143
< S and < T are complimentary
if < S = 64, then < T = (90 - 64) = 26
< C and < D are supplementary
if < C = 83, the < D = (180 - 83) = 97
cant read all of the last one.....but if they are complimentary, and
< U = 41, then the other angle is : (90 - 41) = 49
Answer:
j=1
Step-by-step explanation:
5=3j+2
3j=3
j=1
2 - 6 ÷ 6 (Order of Operations - PEMDAS)
= 2 - 1
= 1
Answer is 1
