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marusya05 [52]
3 years ago
6

Please help I’m desperate for the answer

Mathematics
1 answer:
Fantom [35]3 years ago
6 0

The domain is the input value of an equation/ graph, which is the X value.

The X value on a graph is the horizontal axis across the bottom.

The X-axis for this is the months, so the answer is The domain represents a 11-month period of flower production.

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The entire graph of the function h is shown below write the domain and range of h using interval notation.
telo118 [61]

you can only see values of x Ranging from $-3$ to $3$ and they're included, so domain is $[-3,3]$

and $y$ values ranging from $-2$ to $4$ but $-2$ is not included so range is $(-2,4]$

4 0
3 years ago
The route used by a certain motorist in commuting to work contains two intersections with traffic signals. The probability that
tekilochka [14]

Answer:

a) P(X∩Y) = 0.2

b) P_1 = 0.16

c) P = 0.47

Step-by-step explanation:

Let's call X the event that the motorist must stop at the first signal and Y the event that the motorist must stop at the second signal.

So, P(X) = 0.36, P(Y) = 0.51 and P(X∪Y) = 0.67

Then, the probability P(X∩Y) that the motorist must stop at both signal can be calculated as:

P(X∩Y) = P(X) + P(Y) - P(X∪Y)

P(X∩Y) = 0.36 + 0.51 - 0.67

P(X∩Y) = 0.2

On the other hand, the probability P_1 that he must stop at the first signal but not at the second one can be calculated as:

P_1 = P(X) - P(X∩Y)

P_1 = 0.36 - 0.2 = 0.16

At the same way, the probability P_2 that he must stop at the second signal but not at the first one can be calculated as:

P_2 = P(Y) - P(X∩Y)

P_2 = 0.51 - 0.2 = 0.31

So, the probability that he must stop at exactly one signal is:

P = P_1+P_2\\P=0.16+0.31\\P=0.47

7 0
3 years ago
6x 4y y 5 -2 3x 6 how can I solve this
WITCHER [35]

Answer:

Look below at the image I have provided for you <3

Step-by-step explanation:

I hope this helps!

5 0
2 years ago
Write three different improper fractions that equal 4 1/2
salantis [7]
18/4ths, 27/6ths, and 36/8ths.
6 0
3 years ago
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Taven mixes 18 liters of 14% acid solution with a 35% acid solution, which results in 23% acid solution.
miv72 [106K]
(0.35x + 0.14 * 18) / y = 0.23
x + 18 = y
4 0
3 years ago
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