How can i solve this 4(3x-1)=3+8x-11
2 answers:
4(3x−1)=3+8x−11
Simplify
4(3x−1)=3+8x−11
(4)(3x)+(4)(−1)=3+8x+−11(Distribute)
12x+−4=3+8x+−11
12x−4=(8x)+(3+−11)(Combine Like Terms)
12x−4=8x+−8
12x−4=8x−8
Subtract 8x from both sides.
12x−4−8x=8x−8−8x
4x−4=−8
Add 4 to both sides.
4x−4+4=−8+4
4x=−4
Divide both sides by 4.
4x/4=−4/4
x=−1
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