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Lelu [443]
3 years ago
5

How can i solve this 4(3x-1)=3+8x-11

Mathematics
2 answers:
Tems11 [23]3 years ago
6 0
4(3x−1)=3+8x−11

Simplify

4(3x−1)=3+8x−11

(4)(3x)+(4)(−1)=3+8x+−11(Distribute)

12x+−4=3+8x+−11

12x−4=(8x)+(3+−11)(Combine Like Terms)

12x−4=8x+−8

12x−4=8x−8

Subtract 8x from both sides.

12x−4−8x=8x−8−8x

4x−4=−8

Add 4 to both sides.

4x−4+4=−8+4

4x=−4

Divide both sides by 4.

4x/4=−4/4

x=−1

Stells [14]3 years ago
3 0
12x-4=3+8x-11
4x=-4
x=-1
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Brainliest to most helpful! Answer asap!
kap26 [50]

ΔAOB is a right angled triangle. Therefore the Pythagorean Theorem applies in this situation.
θ is the angle from a standard position of the line OA

The length of the y component is √(1-0)2 +(-3-(-3))2] =√(12+ 02) = 1 A(-3,1) to B(-3,0) which is opposite

Then the length of the x-component is √[(-3-0)2 +(0-0)2] = √(9+0)= 3 B(-3,0) to O(0,0) which is adjacent

The length of vector OA is √[(-3-0)2 + (1-0)2] = √(9+1) = √(10) A(-3,1) to O(0,0) which is the hypotenuse of the triangle

θ = 180 - α
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cosθ = adjacent/hypotenuse = -3/√10
tanθ = opposite/adjacent = 1/-3 = -1/3

α= arcsin(1/√10) ≈ 18
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