Answer:
The plan is:
A fixed cost of $50 per month.
An extra of $15 per GB used over the limit of 2B.
We can write this as a linear equation:
C(x) = $15*x + $50
C(x) is the monthly cost, and x is the number of GB that she used over the limit.
Then, if she used 3GB over the limit, we should replace x by 3.
C(3) = $15*3 + $50 = $45 + $50 = $95.
And the answer to the second question was already found, if she used xx GB in the month, then we have:
C(xx) = $15*xx + $50
(we replaced the x in the general equation by xx)
Change the 30% into a decimal
so its .3
then multiply 2075/.3
and you get $622.50
Answer:
It is not a Type I error neither a Type II error.
Step-by-step explanation:
Let
be the true mean match score. The null hypothesis is
and the alternative hypothesis is
(upper-tail alternative). When the test shows that the mean match score is more than 80 when actually is equal to 80 a Type I error is made. On the other hand, when the test shows that the mean match score is equal to 80 when actually is more than 80 a type II error is made. Therefore, when the test shows that the mean match score is more than 80 when the person does not actually have a fingerprint match, does not correspond to a Type I error neither to a Type II error.
Weight of one large bead is 1.5 grams and weight of one small bead is 8.75 grams.
Step-by-step explanation:
Let,
Weight of one large bead = x
Weight of one small bead = y
According to given statement;
12x+8y=88 Eqn 1
5x+2y=25 Eqn 2
Multiplying Eqn 2 by 4

Subtracting Eqn 1 from Eqn 3

Dividing both sides by 8

Putting x=1.5 in Eqn 1

Dividing both sides by 8

Weight of one large bead is 1.5 grams and weight of one small bead is 8.75 grams.
Keywords: linear equation, elimination method
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