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CaHeK987 [17]
2 years ago
14

The whole cake is 9 cm high and 20 cm across. Each layer of cake is 2cm thick, and each layer is separated by 1 cm of frosting.

Mathematics
1 answer:
Digiron [165]2 years ago
6 0

Answer:

PO

Step-by-step explanation:

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Can someone problem solve a side of a square?
bekas [8.4K]

Answer:

yeah

Step-by-step explanation:

give me the pic and ill solve

the area of the square is 144 square meters. the length is 12 m

6 0
2 years ago
Which of these fractions is equivalent 1/8?<br> A.3/24<br> B.2/9<br> C.1/16<br> D.9/17<br> E.11/18
Brrunno [24]

Answer:A:3/24

Step-by-step explanation:

It’s basic math

4 0
2 years ago
Can these side lengths make a triangle 12,13,7 ?<br> yes<br> no<br> are in possible
notsponge [240]
Answer: I think it’s yes?
3 0
2 years ago
Use the triangle below to find cos V.
Semenov [28]

Answer:

cos\ V = \frac{2\sqrt{29}}{29}

Step-by-step explanation:

Given

The attached triangle

Required

Find cos V

In trigonometry:

cos\theta = \frac{Adjacent}{Hypotenuse}

In this case:

cos V= \frac{TV}{UV}

Where

TV = 6

and

UV^2 = TV^2 + TU^2 -- Pythagoras

UV^2 = 6^2 + 15^2

UV^2 = 261

Take square roots

UV = \sqrt{261

UV = \sqrt{9*29

UV = \sqrt{9} *\sqrt{29

UV = 3\sqrt{29

So:

cos V= \frac{TV}{UV}

cos\ V = \frac{6}{3\sqrt{29}}

cos\ V = \frac{2}{\sqrt{29}}

Rationalize:

cos\ V = \frac{2}{\sqrt{29}}*\frac{\sqrt{29}}{\sqrt{29}}

cos\ V = \frac{2\sqrt{29}}{29}

8 0
2 years ago
Is k=6 a solution to the equation: 1/3k = 3
Step2247 [10]

Answer: No it's not

Step-by-step explanation:

1/3 x 6/1 = 6/3

6/3 = 2

8 0
2 years ago
Read 2 more answers
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