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liubo4ka [24]
3 years ago
8

What's smaller 4/5 or 7/10

Mathematics
2 answers:
wel3 years ago
7 0
7/10 is larger bc 4/5 would be 8/10
Delicious77 [7]3 years ago
5 0

7/10 is smaller than 4/5

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PLEASE HELP ASAP!!!!
Fynjy0 [20]

Answer:

It is not valid since there is more than one variable being changed at one.

Step-by-step explanation:

Jackson changed the brand of soil, but he also changes the amount of water, and the amount of sunlight the plants are receiving, so his conclusion that the soil was more effective is not valid.

6 0
3 years ago
A local gym instructor has a course load that allows her to teach eight classes. At an interest meeting, 8 people wanted high-­‐
cricket20 [7]

Answer:

<u>The final curse load of the local gym instructor is this:</u>

<u>High-­‐impact aerobics = 1</u>

<u>Low-­‐impact aerobics =  4</u>

<u>Jazzercise = 1</u>

<u>Step exercise = 2</u>

Step-by-step explanation:

1. Let's apportion the class load using the Hamilton method

Number of classes the local gym instructor can teach = 8

Total number of students that want to take a class = 114 (8 people wanted high-­‐impact aerobics, 64 wanted low-­‐impact aerobics, 11 wanted jazzercise, and 31 wanted step exercise)

Standard divisor = 114/8 = 14.25

Now, we can apportion the students in in Standard quotas, this way:

High-­‐impact aerobics = 8/14.25 = 0.5614

Low-­‐impact aerobics = 64/14.25 = 4.49

Jazzercise = 11/14.25 = 0.7719

Step exercise = 31/14.25 = 2.1754

Now, we find the Minimum quota, just considering the whole number and don't taking into account the decimals, this way:

High-­‐impact aerobics = 0

Low-­‐impact aerobics =  4

Jazzercise = 0

Step exercise = 2

As we can see we have 6 classes and there are 2 still pending. Those 2 goes to the classes with the highest decimal portion, in this case, Jazzercise .7719 and High-­‐impact aerobics with .5614.

<u>The final course load is this:</u>

<u>High-­‐impact aerobics = 1</u>

<u>Low-­‐impact aerobics =  4</u>

<u>Jazzercise = 1</u>

<u>Step exercise = 2</u>

7 0
3 years ago
Find the angle between the given vectors to the nearest tenth of a degree. u = , v = (2 points)
Liono4ka [1.6K]

Answer:

<h2>3.6°</h2>

Step-by-step explanation:

The question is incomplete. Here is the complete question.

Find the angle between the given vectors to the nearest tenth of a degree.

u = <8, 7>, v = <9, 7>

we will be using the formula below to calculate the angle between the two vectors;

u*v = |u||v| cos \theta

\theta is the angle between the two vectors.

u = 8i + 7j and v = 9i+7j

u*v = (8i + 7j )*(9i + 7j )

u*v = 8(9) + 7(7)

u*v = 72+49

u*v = 121

|u| = √8²+7²

|u| = √64+49

|u| = √113

|v| = √9²+7²

|v| = √81+49

|v| = √130

Substituting the values into the formula;

121= √113*√130 cos θ

cos θ = 121/121.20

cos θ = 0.998

θ = cos⁻¹0.998

θ = 3.6° (to nearest tenth)

Hence, the angle between the given vectors is 3.6°

5 0
3 years ago
Replace? with =, &gt;, or &lt; to make the statement true. 16 ÷ 4 + 12? 4 + 24 ÷ 2
AleksAgata [21]
<em><u>16/4+12 ? 24/2</u></em>
<em><u>4+12 ? 12</u></em>
<em><u>16 ? 12</u></em>
<em><u>?=></u></em>

<em><u>ANSWER: A - ></u></em>
6 0
3 years ago
There are 750 toothpicks in a regular sized box. If a jumbo box is made by doubling all the dimensions of the regular sized box,
Serga [27]

To answer this, let the 3 sides of the regular sized rectangular box be x, y, and z.

When we double all the sides, the new sides have lengths 2x, 2y, and 2z, respectively.

Since the regular box (with dimensions x,y, and z) have 750 toothpicks, we can write

xyz=750

Similarly we can write for the jumbo box as,

(2x)(2y)(2z)

which is equal to 8(xyz)

So this is 8 times the original of xyz. Hence the jumbo box will have 8 times 750 number of toothpicks.

ANSWER: 8*750=6000 toothpicks

7 0
3 years ago
Read 2 more answers
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