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Reil [10]
3 years ago
10

Help me please *an image is attached*

Mathematics
1 answer:
maksim [4K]3 years ago
7 0
I think 4 and -4 the pics are kinda blurry tho
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Rewrite this standard form quadratic equation into vertex form by completing the square. Upload your work here to show your thin
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Solution :

Given the equation :

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$y=1(x^2 - 6x +9)-9+3$

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Therefore the vertex form of $y = x^2 - 6x+3 $  is  $y=1(x-3)^2- 6$.

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