3 years ago

Help me please an image is attached

Mathematics

1 answer:

maksim [4K]3 years ago

7 0

I think 4 and -4 the pics are kinda blurry tho

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Rewrite this standard form quadratic equation into vertex form by completing the square. Upload your work here to show your thin

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Solution :

Given the equation :

$y = x^2 - 6x+3$

$y=1(x^2 - 6x +n)+3$

$n = \left(\frac{b}{2}\right)^2$

$n = \left(\frac{6}{2}\right)^2$

n = 9

$y=1(x^2 - 6x +9-9)+3$

$y=1(x^2 - 6x +9)-9+3$

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Help me please *an image is attached*

Help me please an image is attached