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lys-0071 [83]
3 years ago
15

A company manufactured a 16-oz box of cereal. Boxes are randomly weighted to ensure the correct amount. If the discrepancy in we

ight is more than 0.15 oz, the production is stopped. What is the range of acceptable values for production to continue?
Mathematics
2 answers:
AlexFokin [52]3 years ago
4 0

Answer:

The acceptable range will be : 15.85 oz to 16.15 oz

Step-by-step explanation:

Let the weight of the box be = x

As given,

If the discrepancy in weight is more than 0.15 oz, the production is stopped.

And if the discrepancy in weight is less than 0.15 oz then the production will continue.

We can express this as : If |x-16| \leq 0.15 ; the production continues

|z| \leq a or we can say

-a\leq z\leq a

Now, z = x-16, and a=0.15, then the value becomes,

-0.15 \leq x-16 \leq 0.15

Solving for x:

We get the final range as :

-0.15+16 \leq x-16+16 \leq 0.15+16

15.85\leq x \leq 16.15

Therefore, the answer is : 15.85\leq x \leq 16.15

Katena32 [7]3 years ago
3 0
15.85 oz to 16.15 since .15 ounces less than 16 is 15.85 and .15 ounces more than 16.15
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Georgia [21]

Answer:

V(x) = -\frac{340}{3}x +2220

V(8) = 1313.3

Step-by-step explanation:

Given

Let x represent years and V represents the value.

So, we have:

(x_1,v_1) = (0,2220)

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Solving (a): The linear function

First, we calculate the slope (m)

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This gives:

m = \frac{1540-2220}{6-0}

m = \frac{-680}{6}

m = -\frac{340}{3}

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m = -\frac{340}{3}

So, we have:

v - 1540 = -\frac{340}{3}(x - 6)

Open bracket

v - 1540 = -\frac{340}{3}x +\frac{340}{3}* 6

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Make v the subject

v = -\frac{340}{3}x +680+1540

v = -\frac{340}{3}x +2220

So, the function is:

V(x) = -\frac{340}{3}x +2220

Solving (b): When x = 8

Substitute 8 for x in V(x) = -\frac{340}{3}x +2220

V(8) = -\frac{340}{3}*8 +2220

V(8) = -\frac{340*8}{3} +2220

V(8) = -\frac{2720}{3} +2220

Take LCM

V(8) = \frac{-2720+2220*3}{3}

V(8) = \frac{-2720+6660}{3}

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2 years ago
The map shows the location of the airport and a warehouse in a city. Though not displayed on the map, there is also a factory 10
LekaFEV [45]
Step 1
find the coordinates of the factory
the <span>factory is 104 miles due north of the warehouse

the coordinates of the warehouse are (39,-52)
coordinates of the factory------> (39,-52+104)------> (39,52)

step 2

find the distance warehouse to airport
let
A coordinates of warehouse-------> A( 39,-52)
B coordinates of airport---------> B(-39,52)
C coordinates of factory-------> C(39,52)

distance AB=</span>√[(52+52)²+(-39-39)²]------> distance AB=130 miles
<span>
step 3
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B(-39,52)
</span>C(39,52)
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<span>the total number of miles=distance AB+distance BC---> 130+39
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</span>
the answer is
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