Answer:
A
Step-by-step explanation:
the first part is definetly triangle b is a reflection of triangle a across the x axis i can't see the bottom part of the last answer but I'm pretty sure A would be correct because triangle c may be a rotation but it's most likely not a reflection of triangle a
9514 1404 393
Answer:
- 2nd force: 99.91 lb
- resultant: 213.97 lb
Step-by-step explanation:
In the parallelogram shown, angle B is the supplement of angle DAB:
∠B = 180° -77°37' = 102°23'
Angle ACB is the difference of angles 77°37' and 27°8', so is 50°29'.
Now, we know the angles and one side of triangle ABC. We can use the law of sines to solve for the other two sides.
BC/sin(A) = AB/sin(C)
AD = BC = AB·sin(A)/sin(C) = (169 lb)sin(27°8')/sin(50°29') ≈ 99.91 lb
AC = AB·sin(B)/sin(C) = (169 lb)sin(102°23')/sin(50°29') ≈ 213.97 lb
So the equation is parallel and the slope will be 2
y=0.6x+b
sub in(-2,2) for x and y to find b
2=0.6(-2)+b
2+1.2=b
b=3.2
therefore the equation is y=0.6x+3.2
Answer:
left 7
Step-by-step explanation:
Answer: 0.09
Step-by-step explanation:
Divide 0.27 by 3
M=.09
