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Nezavi [6.7K]
3 years ago
12

Which congruence theorem can be used to prove bda = bdc Hlssa aas sss

Mathematics
2 answers:
Crank3 years ago
7 0

Answer: the answer is sss

Step-by-step explanation:

ozzi3 years ago
4 0
Given that ΔBDA is similar to ΔBDC and:
AD≡DC
AB≡BC
BD≡BD (shared side)
then the best postulate to use is the side-side-side (SSS) postulate.
Answer: SSS
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What is equivelant to 5 to the power of -1?
Mazyrski [523]
\frac{1}{5} Or  0.2
3 0
3 years ago
There are 32 female performers in a dance recital. The ratio of men to women is 3:8. How many men are in the dance recital??????
nydimaria [60]

Answer:

12

Step-by-step explanation:

3/8=x/32

8x=96/32

x=12

6 0
3 years ago
I need to know the answer
Lynna [10]
It would be 3/16.
In the previous post you had 54 which you didn't put into a fraction.

6x-3/2-3x=5/4-x-2
Which simplifies to:
4x-3/2=-3/4
4x=3/4
Turn the denominator to 16 by 4 and also multiply the top by 4 which becomes 12/16.
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5 0
3 years ago
Read 2 more answers
3. guarts. equal. cups
Gnom [1K]


There are 4 cups in 1 quart.

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Hope this helps. :)

5 0
3 years ago
Read 2 more answers
Prime factorization of a 4- digit number with at least three distinct factors
denpristay [2]

Answer:

We know that every number can be written as a product of prime numbers.

The method to find the factorized form of a number depends on the number, we just try to find the different factors by dividing by them, for example for the number 1000 we have:

1000 is an even number, then we can divide it by 2 (2 is a prime number)

1000 = 2*500   (so we already found a prime factor)

500 is also an even number, so we can divide it by 2

1000 = 2*500 = 2*2*250  (we found another prime factor)

dividing by 2 again we get:

1000 = 2*2*250 = 2*2*2*125

1000 = (2*2*2)*125

now we just need to factorize 125

we know that 125 is a multiple of 5, such that:

125 = 5*25 = 5*5*5

(5 is a prime number, so it is completely factorized).

Then the factorization of 1000 is:

1000 = (2*2*2)*(5*5*5) = 2^3*5^3

Now with another example, 1422

1422 is an even number, so we again start using the factor 2:

1422 = 2 = 711

then:

1422 = 2*711

we already found a factor.

711 is a multiple of 3 (the sum of its digits is a multiple of 3), then:

711/3 = 237

We can write our number as:

1422 = 2*3*237

237 is also a multiple of 3

237/3 = 79

then:

1422 = 2*3*3*79

and 79 is a prime number, so we already have 1422 completely factorized.

8 0
2 years ago
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