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Nezavi [6.7K]
3 years ago
12

Which congruence theorem can be used to prove bda = bdc Hlssa aas sss

Mathematics
2 answers:
Crank3 years ago
7 0

Answer: the answer is sss

Step-by-step explanation:

ozzi3 years ago
4 0
Given that ΔBDA is similar to ΔBDC and:
AD≡DC
AB≡BC
BD≡BD (shared side)
then the best postulate to use is the side-side-side (SSS) postulate.
Answer: SSS
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Expand (a+b)^7 using pascal triangle
Inga [223]

(a+b)^7= a^7+ 7a^7b+ 21 a^6b²+ 35a^5b³+ 35 a⁴b⁴+ 21 a³b^5 + 7a²b^6 + b^7

8 0
3 years ago
Find all solutions to the equation. <br><br> cos^2x + 2 cos x + 1 = 0
mixas84 [53]
\cos^2(x)+2\cos(x)+1=0\\\\ (\cos(x)+1)^2=0\\\\ \text{So:}\\\\ \cos(x)+1=0\\\\ \cos(x)=-1\\\\ \boxed{x=\pi+2k\pi},~k\in\mathbb{Z}
5 0
3 years ago
Read 2 more answers
Canada has a population of 1/10 as large as the United States and Canada population is about 32 million about how many people li
Jlenok [28]

Answer:

Step-by-step explanation: If Canada(C) is 32,000,000 and America is A and C x 10 = A then 32,000,000 x 10 = A

And to multiply any whole number by 10 you just add a zero to the end so

320,000,000  is the answer which is pronounced "Three hundred twenty million" And there is 7 zeros in the answer

hope this helps mark me brainliest

6 0
3 years ago
Becky bought a bag of mixed chocolates that have either a toffee or nut center. Her and four friends pulled out the first eleven
denpristay [2]

Answer

Part A

Probability that the next chocolate will have a toffee center = (8/11)

Part B

Expected number of chocolates with nut centers = 18 nut centers

Part C

Probability of the picking three consecutive chocolates with nut centers

= (27/1331)

= 0.0203

Explanation

The first 11 chocolates had 8 toffee and 3 nut centers.

The result from these first 11 picks will be used to calculate the rest of the probability or make predictions.

So, for the first part of the question.

Probability that the next chocolate will have a toffee center

= (8/11)

Part B

If there are 66 chocolates left in the bag, how many do you expect to have a nut center?

Probability of picking a chocolate with nut center = p = (3/11)

Number of chocolates in total = n = 66

Expected number of chocolates with nut centers

= np

= (66) (3/11)

= 18 nut centers

Part C

What is the probability that the next 3 pulled do have a nut in the center?​

Probability of picking a chocolate with nut center = (3/11)

Probability of the picking three consecutive chocolates with nut centers

= (3/11) × (3/11) × (3/11)

= (27/1331)

= 0.0203

Hope this Helps!!!

3 0
1 year ago
I just need to find the value of b
WITCHER [35]

Answer:

straight line add up to 180 so subtract 42 from 180 thts ur answer

8 0
2 years ago
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