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Volgvan
4 years ago
11

What is 49×84÷5×6+26​

Mathematics
2 answers:
mixer [17]4 years ago
4 0

Answer:

4965.2

Step-by-step explanation:

lions [1.4K]4 years ago
3 0
This is the answer 4,965.2
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Drag and drop the following fractions and plot them on the number line. 3/8. 2 7/8. 1 3/4
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Harry styles is always the answer
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3 years ago
It is known that there only is 1% chance of getting a disease. a test is being devised to detect the disease. the probability th
Cerrena [4.2K]
Suppose D is the event that a given patient has the disease, and P is the event of a positive test result.

We're given that

\mathbb P(D)=0.01
\mathbb P(P\mid D)=0.98
\mathbb P(P^C\mid D^C)=0.95

where A^C denotes the complement of an event A.

a. We want to find \mathbb P(P^C). By the law of total probability, we have

\mathbb P(P^C)=\mathbb P(P^C\cap D)+\mathbb P(P^C\cap D^C)

That is, in order for P^C to occur, it must be the case that either D also occurs, or D^C does. Then from the definition of conditional probability we expand this as

\mathbb P(P^C)=\mathbb P(D)\mathbb P(P^C\mid D)+\mathbb P(D^C)\mathbb P(P^C\mid D^C)

so we get

\mathbb P(P^C)=0.01\cdot0.02+0.99\cdot0.95=0.9407

b. We want to find \mathbb P(D\mid P). Now, we can use Bayes' rule, but if you're like me and you find the formula a bit harder to remember, we can easily derive it.

By the definition of conditional probability,

\mathbb P(D\mid P)=\dfrac{\mathbb P(D\cap P)}{\mathbb P(P)}

We have the probabilities of P/P^C occurring given that D/D^C occurs, but not vice versa. However, we can expand the probability in the numerator to get a probability in terms of P being conditioned on D:

\mathbb P(D\cap P)=\mathbb P(D)\mathbb P(P\mid D)

Meanwhile, the law of total probability lets us rewrite the denominator as

\mathbb P(P)=\mathbb P(P\cap D)+\mathbb P(P\cap D^C)

or in terms of conditional probabilities,

\mathbb P(P)=\mathbb P(D)\mathbb P(P\mid D)+\mathbb P(D^C)\mathbb P(P\mid D^C)

so that

\mathbb P(D\mid P)=\dfrac{\mathbb P(D)\mathbb P(P\mid D)}{\mathbb P(D)\mathbb P(P\mid D)+\mathbb P(D^C)\mathbb P(P\mid D^C)}

which is exactly what Bayes' rule states. So we get

\mathbb P(D\mid P)=\dfrac{0.01\cdot0.98}{0.01\cdot0.98+0.99\cdot0.05}\approx0.1653
6 0
3 years ago
The sum of a number times 6 and 21 is at least 24. <br> what's the inequality
Alex777 [14]

Answer:

x ≥ 1/2

Step-by-step explanation:

6x + 21 ≥ 24

6x ≥ 3

x ≥ 1/2

check: (1/2 x 6) + 21 = 24

4 0
3 years ago
Delta bought a new iPhone XS that was discounted so that she got 22% off the original price. This resulted in a $149.60 discount
Mumz [18]

Answer: 159.5

Step-by-step explanation:

If 22% if is 9.90 you add 149.60+ 9.90 and you get 159.5. I'm sorry if this is wrong, I tried

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3 years ago
Read 2 more answers
What is the equation of the line that passes through the point (4, -8) and has a<br> slope of 1/2
Ivanshal [37]

Answer:

y=1/2x-10

Step-by-step explanation:

y=1/2x+b

-8=1/2(4)+b

-8=2+b

-10=b

y=1/2x-10

4 0
3 years ago
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