Question

Please help me with statement and reasoning for this question

Answer 1

Answer:

Hence proved Δ AMD ≅ Δ CMD by SAS rule

Step-by-step explanation:

Given:

Triangle in the attachment.

Δ ABC is an Isosceles triangle

∠ A = ∠ C, AB = BC

Segment BM is median to base segment AC

∴ AM= MC

Solution

Now by Side-Angle-Side congruent property

Δ ABM ≅ Δ CBM

∴ ∠ BMA = ∠ BMC

∴ ∠ DMA = ∠ DMC

Now, In Δ AMD and Δ CMD

AM = MC (median)

∠ DMA = ∠ DMC (DM is Common in both)

Hence By S.A.S

Δ AMD ≅ Δ CMD  hence proved