1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Elodia [21]
3 years ago
5

What's y^2=0+4 What's the answer and how do I complete this?

Mathematics
1 answer:
asambeis [7]3 years ago
6 0
If you're taking 0+4=y^2
It would be y^2=4
And then you take the square root or four which is 2.
So y=2
You might be interested in
Which of the following is true about a parallelogram?
IgorC [24]
I think the answer is B. idk if im right and im sorry if im wrong
6 0
3 years ago
Read 2 more answers
Find the value of x in 2x+20=3x-8
Savatey [412]

Answer:

X=28

Step-by-step explanation:

3x-8=2x+20. So x=28

8 0
3 years ago
Read 2 more answers
Help<br><br> (5a-3a^3)*(4a-1)
ivann1987 [24]

Answer:

-12a^{4}  + 3a^{3} + 20a^{2} -5a

Step-by-step explanation:

(5a-3a^{3} ) • (4a-1)

Let's use FOIL (first, outer, inner, last) to solve this. We'll multiply the terms by one another in that fashion.

20a^{2} - 5a - 12a^{4} + 3a^{3}

Rearrange in decreasing exponents.

-12a^{4}  + 3a^{3} + 20a^{2} -5a

3 0
3 years ago
How do you put 8/100 ,3/5 ,7/10 from least to greatest
emmainna [20.7K]
From least to Greatest: 8/100, 7/10, 3/5
3 0
3 years ago
Read 2 more answers
For the given term, find the binomial raised to the power, whose expansion it came from: 15(5)^2 (-1/2 x) ^4
Elina [12.6K]

Answer:

<em>C.</em> (5-\frac{1}{2})^6

Step-by-step explanation:

Given

15(5)^2(-\frac{1}{2})^4

Required

Determine which binomial expansion it came from

The first step is to add the powers of he expression in brackets;

Sum = 2 + 4

Sum = 6

Each term of a binomial expansion are always of the form:

(a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......

Where n = the sum above

n = 6

Compare 15(5)^2(-\frac{1}{2})^4 to the above general form of binomial expansion

(a+b)^n = ......+15(5)^2(-\frac{1}{2})^4+.......

Substitute 6 for n

(a+b)^6 = ......+15(5)^2(-\frac{1}{2})^4+.......

[Next is to solve for a and b]

<em>From the above expression, the power of (5) is 2</em>

<em>Express 2 as 6 - 4</em>

(a+b)^6 = ......+15(5)^{6-4}(-\frac{1}{2})^4+.......

By direct comparison of

(a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......

and

(a+b)^6 = ......+15(5)^{6-4}(-\frac{1}{2})^4+.......

We have;

^nC_ra^{n-r}b^r= 15(5)^{6-4}(-\frac{1}{2})^4

Further comparison gives

^nC_r = 15

a^{n-r} =(5)^{6-4}

b^r= (-\frac{1}{2})^4

[Solving for a]

By direct comparison of a^{n-r} =(5)^{6-4}

a = 5

n = 6

r = 4

[Solving for b]

By direct comparison of b^r= (-\frac{1}{2})^4

r = 4

b = \frac{-1}{2}

Substitute values for a, b, n and r in

(a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......

(5+\frac{-1}{2})^6 = ......+ ^6C_4(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+ ^6C_4(5)^{6-4}(\frac{-1}{2})^4+.......

Solve for ^6C_4

(5-\frac{1}{2})^6 = ......+ \frac{6!}{(6-4)!4!)}*(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+ \frac{6!}{2!!4!}*(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+ \frac{6*5*4!}{2*1*!4!}*(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+ \frac{6*5}{2*1}*(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+ \frac{30}{2}*(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+15*(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+15(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+15(5)^2(\frac{-1}{2})^4+.......

<em>Check the list of options for the expression on the left hand side</em>

<em>The correct answer is </em>(5-\frac{1}{2})^6<em />

3 0
3 years ago
Other questions:
  • How do you find a vector of length 10 in the direction of vequals=left angle 3 comma negative 2 right angle3,−2​?
    13·1 answer
  • Can someone help me with this question
    9·1 answer
  • What is 5.8 × 106 mg/s in grams per minute?
    12·1 answer
  • Solve the linear system of equations using the linear combination method.
    5·1 answer
  • Help!!! I need some to explain this problem to me! I don’t have much time!!
    10·1 answer
  • Anyone wanna chat?? =&gt;
    5·2 answers
  • Jonathan worked at McDonalds 20 hours per week and earned $195. Use the equation 20h=195 to find Jonathan's hourly wage.
    7·2 answers
  • ^^^Can someone help ^^^
    6·1 answer
  • 10(2x+-15)= 40x=30 how do i solve this?
    12·1 answer
  • Find the quotient of <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%28x%5E%7B3%7D%20-%202x%5E%7B2%7D%20%2B%206x%20%2B%203%29%7D%7B
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!