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Tresset [83]
4 years ago
13

A new company estimates its total profit (profit = total revenue minus total cost) as P(x) = x4 – 2x3 – 240x – 35, where P is in

hundreds of dollars and x is the number of months elapsed since the company’s start-up. According to the rational zero theorem, what can be the values of x until the company breaks even?
Mathematics
2 answers:
Zigmanuir [339]4 years ago
6 0
With ruffini you easily get 5.6666 months
Monica [59]4 years ago
5 0

Answer: \pm 1,\pm5,\pm7,\pm35

Step-by-step explanation:

Given: A new company estimates its total profit as

P(x) = x^4 - 2x^3 - 240x - 35, where P is in hundreds of dollars and x is the number of months elapsed since the company’s start-up.

The coefficient of the leading term (a)= 1

The constant term = 35

The factors of 35 (b)=\pm 1,\pm5,\pm7,\pm35

By rational root theorem , we have

The rational zeros \dfrac{b}{a}=\frac{\pm 1}{ 1},\dfrac{\pm 5}{1},\dfrac{\pm7}{1},\dfrac{\pm35}{1}

Hence, the values of x until the company breaks even = \pm 1,\pm5,\pm7,\pm35

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irina [24]

Answer:

2/28 ?

Step-by-step explanation:

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7 0
2 years ago
How do I factor 125x^3+8
xeze [42]
Step 1 :

53x3 - 8
Step 2 :

Trying to factor as a Difference of Cubes:

2.1 Factoring: 125x3-8

Theory : A difference of two perfect cubes, a3 - b3 can be factored into
(a-b) • (a2 +ab +b2)

Proof : (a-b)•(a2+ab+b2) =
a3+a2b+ab2-ba2-b2a-b3 =
a3+(a2b-ba2)+(ab2-b2a)-b3 =
a3+0+0+b3 =
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Check : 125 is the cube of 5

Check : 8 is the cube of 2
Check : x3 is the cube of x1

Factorization is :
(5x - 2) • (25x2 + 10x + 4)

Trying to factor by splitting the middle term

2.2 Factoring 25x2 + 10x + 4

The first term is, 25x2 its coefficient is 25 .
The middle term is, +10x its coefficient is 10 .
The last term, "the constant", is +4

Step-1 : Multiply the coefficient of the first term by the constant 25 • 4 = 100

Step-2 : Find two factors of 100 whose sum equals the coefficient of the middle term, which is 10 .

-100 + -1 = -101
-50 + -2 = -52
-25 + -4 = -29
-20 + -5 = -25
-10 + -10 = -20
-5 + -20 = -25

For tidiness, printing of 12 lines which failed to find two such factors, was suppressed

Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored

Final result :

(5x - 2) • (25x2 + 10x + 4)
6 0
3 years ago
Let X be a random variable with probability density function fX(x) = ( c(1 − x 2 ) if − 1 < x < 1 0 otherwise. a) What is
xeze [42]

Answer:

a)   c=3/4

b)  for -1<x<1

 F(x) = (3/4) ( x + (2-x^3)/3 )

c)

  E(x)=0

  Var(x) = 1/5

Step-by-step explanation:

Hi!

a)

In order to f(x) be a probability density function it must be normalized, which means that its integral must be equal to 1:

1 = \int\limits^{\infty}_{-\infty} {f(x)} \, dx

Since f(x) is zero for x>1 and x<-1

1 = \int\limits^1_{-1} {f(x)} \, dx = \int \limits^1_{-1} {c(1-x^2)}\, dx \\\\\\1 = c ((1-\frac{1}{3}) - (-1 - \frac{-1}{3})) = c(\frac{2}{3} - \frac{-2}{3} ) = c\frac{4}{3}

Therefore:

c=3/4

b)

The cumulative distribution fucntion F(x) can be obtained integrating f(x) from -∞ to x:

Since f(x) = 0 for x<-1      

        F(x) = 0 for x<-1

for -1<x<1:

F(x) = \int \limits^x_{-1} f(x')\, dx' = c(x'-\frac{x'^3}{3})^x_{-1} = c (x-\frac{x^3}{3} + \frac{2}{3})\\\\F(x) = \frac{3}{4}(x + \frac{2-x^3}{3})

for x>1

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c)

The mean E(x) can be found integrating  xf(x)

E(x) = \int \limits_{-1}^1 {x f(x)}\, dx

We can easily infer that the mean must be zero, since f(x) is an even function and thus xf(x) is an odd function integrated in a simetric interval:

E(x) = 0

The variance of x, Var(x), can be evaluated integrating  (x-E(x))^2f(x), since E(x)=0:

Var(x) = \int \limits^{1}_{-1} {x^2f(x)}\, dx\\Var(x) = \int \limits^{1}_{-1} {c (x^2 - x^4 )dx}\\Var(x) = c \frac{4}{15}

Since c=3/4

Var(x) = 1/5

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Vinvika [58]

Answer:

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7 0
3 years ago
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NemiM [27]

Answer:

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Step-by-step explanation:

m∠A must be m∠C due to symmetry.

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m∠T = 180 - m∠C - m∠A = 32

5 0
3 years ago
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