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maksim [4K]
4 years ago
9

How to do area of irregular figures

Mathematics
2 answers:
Alex777 [14]4 years ago
6 0
Find the area of the whole rectangle and then subtract the area of the smaller rectangle.

Whole rectangle: 10 * 12 = 120
Small rectangle: 7 * 2 = 14

Area of the figure = 120 - 14 = 106

Hope this helps:)
sleet_krkn [62]4 years ago
5 0
A = (10 x 12) - (2 x 7)
A = 120 - 14
A = 106

answer
106 sq. meters
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BRAINLIEST IF YOU ANSWER
creativ13 [48]

Answer:

24ft

Step-by-step explanation: I could be wrong because I haven't done this for a while but if you add all of the numbers together you should get 24 if I am using the right equation.

4 0
3 years ago
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A box contains 288 sugar cubes. You open the top of the box and count 12 cubes across the front and 6 cubes along a side. How ma
AleksandrR [38]
Hello!

You have to find out how many cubes are in 1 layer

You do this by multiplying the amount across by the amount along the side.

12 * 6 = 72

Divide this by the amount of cubes

288 / 72 = 4

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The answer is 4

Hope this helps!
6 0
3 years ago
Please help if u cannot skip
posledela

The statement that is true about the function is D. it is discontinuous and non-differentiable at x = 3.

<h3>How to determine which statement is true?</h3>

To determine which statement is true, we need to know the conditions for continuity and differentiablity of a function.

<h3>Conditions for continuity and differentiablity of a function.</h3>
  • For a function f(x) to be continuous at a point x = a, then both the left hand limit of f(x) and the right hand limit of f(x) as x → a must be equal. That is \lim_{x \to a^{-} } f(x) =  \lim_{x \to a^{+} } f(x). So,  \lim_{x \to a^{} } f(x) must exist since  \lim_{x \to a^{-} } f(x) =  \lim_{x \to a^{+} } f(x) =  \lim_{x \to a^{} } f(x)
  • Also, for a function to be differentiable at a point x = a, it must also exist at x = a

So, since f(x) = {x² - 1 if -1 ≤ x ≤ 3 and x²/3 if 3 < x ≤ 8}

From the equality on the first condition,we see that f(x) is exists at x = 3 but is not continuous since f(x) changes to another function when x > 3. So,left hand limit of f(x) and the right hand limit of f(x) as x → 3 are not equal.

That is \lim_{x \to 3^{-} } f(x) \neq   \lim_{x \to 3^{+} } f(x) . Thus, the function is discontinuous at x = 3.

For differentiability, both conditions must be met. Since only one condition is met, it is non-differentiable.

So, the function is discontinuous and non-differentiable at x = 3.

So, the statement that is true about the function is D. it is discontinuous and non-differentiable at x = 3.

Learn more about continuity of a function here:

brainly.com/question/24177259

#SPJ1

4 0
2 years ago
to a formula or equation for a specified variable means to rearrange it so that the variable appears alone on one side of the eq
Eddi Din [679]

Yes, you are right. To solve for a variable means to put it on one side by itself, in terms of the other variables or values. To move something to the opposite side you do the opposite operation. Then you do the same thing to both sides of the equation.

4 0
4 years ago
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Best Buy buys an iPod from a wholesaler with a $300 list price and a 5% trade discount. What is the trade discount amount? What
kkurt [141]
Trade discounts are discounts offered to retailers off the list price.
Thus the retailer pays (300)(1-0.05)=$285 (=net cost of the iPod)
8 0
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