Answer:
The expression equivalent to 486-9+6+3^*2 is 500-7+6+5^*2
Step-by-step explanation:
486-9+6+3^*2 = 500-7+6+5^*2
486-9+6+9 = 500-7+6+25
486-24 = 500-38
462 = 462
Answer:
Q(t) = Q_o*e^(-0.000120968*t)
Step-by-step explanation:
Given:
- The ODE of the life of Carbon-14:
Q' = -r*Q
- The initial conditions Q(0) = Q_o
- Carbon isotope reaches its half life in t = 5730 yrs
Find:
The expression for Q(t).
Solution:
- Assuming Q(t) satisfies:
Q' = -r*Q
- Separate variables:
dQ / Q = -r .dt
- Integrate both sides:
Ln(Q) = -r*t + C
- Make the relation for Q:
Q = C*e^(-r*t)
- Using initial conditions given:
Q(0) = Q_o
Q_o = C*e^(-r*0)
C = Q_o
- The relation is:
Q(t) = Q_o*e^(-r*t)
- We are also given that the half life of carbon is t = 5730 years:
Q_o / 2 = Q_o*e^(-5730*r)
-Ln(0.5) = 5730*r
r = -Ln(0.5)/5730
r = 0.000120968
- Hence, our expression for Q(t) would be:
Q(t) = Q_o*e^(-0.000120968*t)
Answer:
20 in
Step-by-step explanation:
Tree 1:
Rate of growth = (½ ft/2 yr)
12 yr growth = 12 × (½/2)
= 6/2
= 3 ft
= 36 in
Tree 2:
Rate of growth = (4 in/3yr)
12 yr growth = 12 × (4/3)
= 48/3
= 16 in
Difference:
Tree 1 - Tree 2 = 36 - 16
= 20 in
The trees will differ in height by 20 in.
Answer:
x = 3
Step-by-step explanation:
take 60 degree as reference angle and using cos rule
cos 60 = adjacent/hypotenuse
1/2 = x/6
do cross multiplication
2*x = 6*1
x = 6/2
x = 3
Answer: because 4 would be greater than 3.
Step-by-step explanation:
