1/2 (6x-4)-(3-x)=ax+x+b
3x - 2 - 3 + x = (a+1)x + b
4x - 5 = (a+1)x +b
compare constants:
b = -5
compare coefficients of x:
a +1 = 4
a = 4-1
a = 3
so, a-b = 3 - (-5) = 8
Answer:
Since this is means data and we do not know the populations standard deviation, a t-interval
needs to be used. The justification is found in checking the conditions needed for a t-interval. The
problem stated it was a random sample so we will assume this is sufficient. Since the sample size is
slightly under 30, we will still check for the data being roughly normal. Either a boxplot or normal
probability plot would suffice. In both cases there is no reason to doubt the sample data are roughly
normally distributed so we can proceed to the calculations.
The interval would be (69, 76)
Explanation:
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