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Nikolay [14]
3 years ago
7

109.72 divided by 6 and then round to the nearest hundredths

Mathematics
2 answers:
Ivahew [28]3 years ago
3 0

Answer:

18.28

Step-by-step explanation:

used google calculator

gizmo_the_mogwai [7]3 years ago
3 0

Answer:

18.3

Step-by-step explanation:

I put 109.72 in my caluator divide it by 6. I got 18.28667 (there's too many 6's so you don't need to worry about) The hundreths is number 8. You rounded up add 1 to the number 2 and you get 3. Your answer is 18.3


The reason why you need to rounded up is becauase the 8 which is in the hundredths is greater than 5, so you add 1. If it's not than greater than 5 don't add one, leave it the way it is.

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What is the equation in point slope form of the line that passes through the points (-3,5) and (2,-3)?
SOVA2 [1]

Answer:

y - (-3) = -8/5 (x - 2)

Step-by-step explanation:

-3 -5 = -8

2 - (-3) = 5

slope = -8/5

y - (-3) = -8/5 (x - 2)


3 0
3 years ago
A mouse is traveling at a rate of 100 feet per hour. One half hour later, a snake smells the
Arlecino [84]

Let, snake catches the mouse in t hours. Till then mouse is travelling from

( t + 1.5 ) hours.

Distance, travelled by mouse in t hours is, d = 100(t+ 1.5) .

To catch the mouse snake had to travel the same distance d in  t hours.

So,

200t = 100(  t + 1.5 )\\\\2t = t + 1.5\\\\t = 1.5 \ hours

Therefore, snake will catch mouse in 1.5 hours.

5 0
3 years ago
These two trapezoids are similar What is the correct way to complete the similarity statement?
pentagon [3]

Option A:

\mathrm{ABCD} \sim \mathrm{GFHE}

Solution:

ABCD and EGFH are two trapezoids.

To determine the correct way to tell the two trapezoids are similar.

Option A: \mathrm{ABCD} \sim \mathrm{GFHE}

AB = GF (side)

BC = FH (side)

CD = HE (side)

DA = EG (side)

So, \mathrm{ABCD} \sim \mathrm{GFHE} is the correct way to complete the statement.

Option B: \mathrm{ABCD} \sim \mathrm{EGFH}

In the given image length of AB ≠ EG.

So, \mathrm{ABCD} \sim \mathrm{EGFH} is the not the correct way to complete the statement.

Option C: \mathrm{ABCD} \sim \mathrm{FHEG}

In the given image length of AB ≠ FH.

So, \mathrm{ABCD} \sim \mathrm{FHEG} is the not the correct way to complete the statement.

Option D: \mathrm{ABCD} \sim \mathrm{HEGF}

In the given image length of AB ≠ HE.

So, \mathrm{ABCD} \sim \mathrm{HEGF} is the not the correct way to complete the statement.

Hence, \mathrm{ABCD} \sim \mathrm{GFHE} is the correct way to complete the statement.

3 0
3 years ago
Evaluate the expression for the given value of the variable(s).
Lesechka [4]
The answer to what you have there is -55 using order of operations. 5 times -6 is -30. 5 times -5 is -25. add. You get -55.
3 0
2 years ago
Read 2 more answers
Area of a triangle with points at (-9,5), (6,10), and (2,-10)
Ann [662]
First we are going to draw the triangle using the given coordinates. 
Next, we are going to use the distance formula to find the sides of our triangle.
Distance formula: d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Distance from point A to point B:
d_{AB}= \sqrt{[6-(-9)]^2+(10-5)^2}
d_{AB}= \sqrt{(6+9)^2+(10-5)^2}
d_{AB}= \sqrt{(15)^2+(5)^2}
d_{AB}= \sqrt{225+25}
d_{AB}= \sqrt{250}
d_{AB}=15.81

Distance from point A to point C:
d_{AC}= \sqrt{[2-(-9)]^2+(-10-5)^2}
d_{AC}= \sqrt{(2+9)^2+(-10-5)^2}
d_{AC}= \sqrt{11^2+(-15)^2}
d_{AC}= \sqrt{121+225}
d_{AC}= \sqrt{346}
d_{AC}= 18.60

Distance from point B from point C
d_{BC}= \sqrt{(2-6)^2+(-10-10)^2}
d_{BC}= \sqrt{(-4)^2+(-20)^2}
d_{BC}= \sqrt{16+400}
d_{BC}= \sqrt{416}
d_{BC}=20.40

Now, we are going to find the semi-perimeter of our triangle using the semi-perimeter formula:
s= \frac{AB+AC+BC}{2}
s= \frac{15.81+18.60+20.40}{2}
s= \frac{54.81}{2}
s=27.41

Finally, to find the area of our triangle, we are going to use Heron's formula:
A= \sqrt{s(s-AB)(s-AC)(s-BC)}
A=\sqrt{27.41(27.41-15.81)(27.41-18.60)(27.41-20.40)}
A= \sqrt{27.41(11.6)(8.81)(7.01)}
A=140.13

We can conclude that the perimeter of our triangle is 140.13 square units.

3 0
2 years ago
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