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svlad2 [7]
3 years ago
10

A bracelet was marked up $50 from cost, which amounts to a 20% increase. Find the original cost of the bracelet

Mathematics
2 answers:
strojnjashka [21]3 years ago
6 0

Answer:

40

Step-by-step explanation:

20% times 50 = 10 thats ten less cuz it asks for the original i think

abruzzese [7]3 years ago
4 0

Answer:

Original cost was $250

Step-by-step explanation:

let x be the original cost

20 = 50/x x 100

20x = 50x 100

20x = 5000

x= 5000/20

x = 250

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ale4655 [162]
This is my answer. Hope that it will help you.

6 0
2 years ago
A professor pays 25 cents for each blackboard error made in lecture to the student who pointsout the error. In a career ofnyears
arsen [322]

Answer:

The correct answer is "0.0000039110".

Step-by-step explanation:

The given values are:

Y_n\rightarrow N(\mu, \sigma^2)

\mu = 40n

\sigma^2=100n

n=20

then,

The required probability will be:

= P(Y_{20}>1000)

= P(\frac{Y_{20}-\mu}{\sigma} >\frac{1000-40\times 20}{\sqrt{100\times 20} } )

= P(Z>\frac{1000-800}{44.7214} )

= P(Z>\frac{200}{44.7214} )

= P(Z>4.47)

By using the table, we get

= 0.0000039110

6 0
2 years ago
Please solve<br>x^2+6x+5=0​
Inessa [10]

Answer:

plus the other number and the other one

8 0
2 years ago
An area is approximated to be 14 in 2 using a left-endpoint rectangle approximation method. A right- endpoint approximation of t
USPshnik [31]
The trapezoidal approximation will be the average of the left- and right-endpoint approximations.

Let's consider a simple example of estimating the value of a general definite integral,

\displaystyle\int_a^bf(x)\,\mathrm dx

Split up the interval [a,b] into n equal subintervals,

[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]

where a=x_0 and b=x_n. Each subinterval has measure (width) \dfrac{a-b}n.

Now denote the left- and right-endpoint approximations by L and R, respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are \{x_0,x_1,\cdots,x_{n-1}\}. Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints, \{x_1,x_2,\cdots,x_n\}.

So, you have

L=\dfrac{b-a}n\left(f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1})\right)
R=\dfrac{b-a}n\left(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n)\right)

Now let T denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

T=\dfrac{b-a}n\left(\dfrac{f(x_0)+f(x_1)}2+\dfrac{f(x_1)+f(x_2)}2+\cdots+\dfrac{f(x_{n-2})+f(x_{n-1})}2+\dfrac{f(x_{n-1})+f(x_n)}2\right)

Factoring out \dfrac12 and regrouping the terms, you have

T=\dfrac{b-a}{2n}\left((f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1}))+(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n))\right)

which is equivalent to

T=\dfrac12\left(L+R)

and is the average of L and R.

So the trapezoidal approximation for your problem should be \dfrac{14+21}2=\dfrac{35}2=17.5\text{ in}^2
4 0
2 years ago
Solve the system by the elimination method.
joja [24]

Answer: B

Step-by-step explanation:

YOU MINUS 4 -4 WHICH IS -8 SO ITS B

8 0
3 years ago
Read 2 more answers
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