1.D 2. A 3.C 4.D
1 Is the monomial as it only contains one expression.
2. Is the difference of squares because something squared minus something squared.
3. Is standard because it is of the form
![a_nx^n+ a_{n-1}x^{n-1}+...+a_1x+a_0](https://tex.z-dn.net/?f=a_nx%5En%2B%20a_%7Bn-1%7Dx%5E%7Bn-1%7D%2B...%2Ba_1x%2Ba_0%20)
4. We know D is the not the monomial simply because its power is negative which means it does not fit the definition of a polynomial.
Answer: The answer is NO.
Step-by-step explanation: The given statement is -
If the graph of two equations are coincident lines, then that system of equations will have no solution.
We are to check whether the above statement is correct or not.
Any two equations having graphs as coincident lines are of the form -
![ax+by=c,\\\\dax+dby=dc,\\\\\textup{where}~~d\neq 1.](https://tex.z-dn.net/?f=ax%2Bby%3Dc%2C%5C%5C%5C%5Cdax%2Bdby%3Ddc%2C%5C%5C%5C%5C%5Ctextup%7Bwhere%7D~~d%5Cneq%201.)
If we take d = 1, then both the equations will be same.
Now, subtracting the second equation from first, we have
![a(1-d)x+b(1-d)y=c(1-d)\\\\\Rightarrow ax+by=c,~\textup{since}~d\neq 1,~\textup{so}~1-d\neq 0.](https://tex.z-dn.net/?f=a%281-d%29x%2Bb%281-d%29y%3Dc%281-d%29%5C%5C%5C%5C%5CRightarrow%20ax%2Bby%3Dc%2C~%5Ctextup%7Bsince%7D~d%5Cneq%201%2C~%5Ctextup%7Bso%7D~1-d%5Cneq%200.)
Again, we will get the first equation, which is linear in two unknown variables. So, the system will have infinite number of solutions, which consists of the points lying on the line.
For example, see the attached figure, the graphs of following two equations is drawn and they are coincident. Also, the result is again the same straight line which has infinite number of points on it. These points makes the solution for the following system.
![2x+5y=10,\\\\6x+15y=30.](https://tex.z-dn.net/?f=2x%2B5y%3D10%2C%5C%5C%5C%5C6x%2B15y%3D30.)
Thus, the given statement is not correct.
Here is your solution.. hope it helps
The slope is 6 because x/y or rise/run and in x equal +1 which is positive 1 and y equal +6 which is positive 6... then you divide y by x which will be 6 divided 1 or 6/1 and that’s how it’s 6 :)