To get the equation of tangent, we need a point on it and its slope.
we already have (x1,y1) = (pi/3,2) on the tangent line.
To get the slope of tangent,
m = derivative of y at the given point.
y = sec x
y' = sec x tan x
at x = pi/3,
y' = sec pi/3 tan pi/3
y'= 2
so the slope of tangent is 2
equation will be
y -y1 = m (x-x1)
y - 2 = 2

(x- pi/3)
Thats your equation of tangent.
you can simplify if you want.
Answer:
the value of the polynomial should be -4
Step-by-step explanation:
Hope this Helped
Quadrilateral ( trapezoid )
Answer:
<u>Answer</u><u> </u><u>→</u><u> </u><u>Student</u><u> </u><u>A</u><u> </u><u>was</u><u> </u><u>right</u><u>.</u>
![{ \tt{ \sqrt[3]{1944} = \sqrt[3]{(72 \times 27)} }} \\ \\ = { \tt{ \sqrt[3]{72} \times \sqrt[3]{27} }} \\ \\ = { \tt{ \sqrt[3]{72} \times 3}} \\ \\ = { \underline{ \tt{ \: 3 \sqrt[3]{72} } \: }}](https://tex.z-dn.net/?f=%7B%20%5Ctt%7B%20%5Csqrt%5B3%5D%7B1944%7D%20%20%3D%20%20%5Csqrt%5B3%5D%7B%2872%20%5Ctimes%2027%29%7D%20%7D%7D%20%5C%5C%20%20%5C%5C%20%20%3D%20%7B%20%5Ctt%7B%20%5Csqrt%5B3%5D%7B72%7D%20%5Ctimes%20%20%5Csqrt%5B3%5D%7B27%7D%20%20%7D%7D%20%5C%5C%20%20%5C%5C%20%20%3D%20%7B%20%5Ctt%7B%20%5Csqrt%5B3%5D%7B72%7D%20%20%5Ctimes%203%7D%7D%20%5C%5C%20%20%5C%5C%20%20%3D%20%7B%20%5Cunderline%7B%20%5Ctt%7B%20%5C%3A%203%20%5Csqrt%5B3%5D%7B72%7D%20%7D%20%5C%3A%20%7D%7D)