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Dennis_Churaev [7]
3 years ago
8

Which equation represents a circle with a center at (2,-3) and a radius of 11

Mathematics
1 answer:
Verdich [7]3 years ago
8 0

Answer:

x^2-4x+y^2+6y-108=0

Step-by-step explanation:

The- equation- of- circle- with -center- at- (h,k) -and -a -radius- of- r -is: \\(x-h)^2 +(y-k)^2 = r^2\\h = 2 , \\  k = -3\\r = 11\\(x-2)^2+(y-(-3))^2 = 11^2\\(x-2)^2+(y+3)^2 = 121\\x^2-4x+4 +y^2+6y+9 = 121\\x^2 -4x+y^2+6y+4+9=121\\x^2 -4x+y^2+6y+13=121\\x^2 -4x+y^2+6y=121-13\\x^2 -4x+y^2+6y= 108\\x^2 -4x+y^2+6y-108 = 0

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2x+28+2x-14
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3 years ago
A social networking site recorded that 80 per-cent of people who became members of the site one month were between 30 and 40 yea
77julia77 [94]

Answer:

x=360          30-40 yrs =288

Step-by-step explanation:

multiple 72 by .05 (36) to find 10 percent, then multiple 80 percent by that number(36) then add both numbers together to get total number of members that month

(72x.05)=36x2+(.80x36)=288

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3 0
3 years ago
A recipe calls for 3 times as many chocolate chips as butterscotch chips. If there are 25 oz of chocolate chips, how many oz do
Bingel [31]

The amount, in oz of butterscotch chips needed by proportional reasoning is; 75oz.

<h3>What is the amount of butterscotch chips needed by proportional reasoning?</h3>

It follows from the task content that the the amount of butterscotch chips needed can be determined by means of the proportion premise declared in which case;

  • The recipe requires 3 times as many chocolate chips as butterscotch chips.

Hence, when 25oz of chocolate chips is used, the amount of butterscotch needed is 3 times 25 and hence, = 3 × 25 = 75oz.

Read more on proportion;

brainly.com/question/1496357

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4 0
1 year ago
Alex had $750,000 he lost 80% how many dollars did he lose ​
Stels [109]

Answer:

$600,000

Step-by-step explanation:

GIven;

Alex had $750,000 he lost 80%

To Find;

How many dollars did he lose ​

Solve;

$750,000 * 80% = 600,000

Hence, Alex lost $600,000.

<em>~Learn with Lenvy~</em>

8 0
2 years ago
Read 2 more answers
During a recent eruption, the volcano spewed out copious amount of ash. One small piece of ash was ejected from the volcano with
nlexa [21]
For question number 1:The plot H = H(t) is the parabola and it reaches its maximum in the moment when exactly at midpoint between the roots t = 0 and t = 23. At that moment t = 23/2 or 11.5 seconds.
For question number 2:To find the maximal height, just simply substitute t = 11.5 into the quadratic equation. The answer would be 22.9.
For question number 3:H(t) = 0,   or, which is the same as -16t^2 + 368t = 0.Factor the left side to get  -16*t*(t - 23) = 0.t = 0, relates to the very start of the process, when the ash started its way up.The other root is t = 23 seconds, and it is precisely the time moment when the bit of ash will go back to the ground.
6 0
3 years ago
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