Why do graphs sometime not have a line through them?

For many years businesses have struggled with the rising cost of health care. But recently, the increases have slowed due to les

kaheart [24]

Answer:

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

The margin of error for this case is given by:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

And replacing we got:

$ME = 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.0259$

And replacing into the confidence interval formula we got:

$0.52 - 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.4941$

$0.52 + 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.5459$

And the 95% confidence interval would be given (0.4941;0.5459).

Step-by-step explanation:

Data given and notation

n=1000 represent the random sample taken

$\hat p=0.52$ estimated proportion of of U.S. employers were likely to require higher employee contributions for health care coverage

$\alpha=0.05$ represent the significance level (no given, but is assumed)

Solution to the problem

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

The margin of error for this case is given by:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

And replacing we got:

$ME = 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.0259$

And replacing into the confidence interval formula we got:

$0.52 - 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.4941$

$0.52 + 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.5459$

And the 95% confidence interval would be given (0.4941;0.5459).

5 0

3 years ago

using the graph,find the value of the constant in the equation below.if necessary,round your answer to the nearest integer (Pict

Ugo [173]

The equation is the form:
Height = Constant / Width

There are several points that can be used to determine the constant. Picking out one which is (4,20)
20 = Constant / 4
Constant = 4(20)
Constant = 80

The constant is 80.

3 0

3 years ago

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Select the number line that shows the decimal for the following fraction.<br><br> sixth tenths

Komok [63]

Answer:

C

Step-by-step explanation:

to figure this out, lets understand how decimals work

a decimal number in the tens place before the decimal

↓ here

0.00

that number will be the same number as the numerator or top number of a fraction in tenths

↓ here

0/10

so say it was 4/10 we needed to find, we would look on the number line for 0.40 like in answer choice B (NOT THE CORRECT ANSWER FOR THIS PROBLEM)

hope this helps you out on your work :)

4 0

3 years ago

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A population of bacteria is initially 2,000. After three hours the population is 1,000.

lina2011 [118]

The population starts at 2000, so a=2000.

We also know that the population in 3 hours is 1000, so we can setup the equation:

2000 b^3 = 1000

This gets us:

b^3 = 1/2

And taking the cube root of both sides gives us:

b ≈ 0.7937005259841

Rounding that to 4 places, we have:

f(t) = 2000 (0.7937)^t

5 0

3 years ago

a walking path across a park is represented by the equation y=-2x-7. A new path will be built perpendicular to this path.The pat

jonny [76]

Answer:

The equation that represents the new path is y=(1/2)x-2

Step-by-step explanation:

step 1

Find the slope of the give line

we have

y=-2x-7

so

the slope m is equal to

m=-2

step 2

Find the slope of the perpendicular line to the given line

Remember that

If two lines are perpendicular, then their slopes are opposite reciprocal of each other

so

we have

m=-2 -----> slope of the given line

therefore

The slope of the perpendicular line is equal to

m=1/2

step 3

With m=1/2 and the point (-2,-3) find the equation of the line

y-y1=m(x-x1)

substitute

y+3=(1/2)(x+2)

y=(1/2)x+1-3

y=(1/2)x-2 -----> equation that represent the new path

8 0

3 years ago

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