Question

Given: f(x) = 2x + 5 and g(x) = x2 and h(x) = -2x h(g(f(x)))

Answer 1

Hello here is a solution :
h(g(f(x))) ?

g(f(x))= g(2x+5)=(2x+5)²=(2x)²+2(2x)(5)+5² = 4x²+20x+25
h(g(f(x)))(x) = h(4x²+20x+25) = -2(4x²+20x+25) 
h(g(f(x)))(x) = -8x²-40x-50

Answer 2

Answer:

$h(g(f(x)))(x) = -8x^2-40x-50$

Step-by-step explanation:

$f(x) = 2x + 5$

$g(x)=x^2$

$h(x)=-2x$

$h(g(f(x)))$, first replace f(x) with 2x+5

$h(g(2x+5))$

Replace 2x+5 for x in g(x). $g(2x+5)=(2x+5)^2= (2x+5)(2x+5)= 4x^2+20x+25$

$h(g(2x+5))$ becomes $h(4x^2+20x+25)$

Replace x with 4x^2+20x+25 in h(x)

$h(4x^2+20x+25)=-2(4x^2+20x+25)=-8x^2-40x-50$