Can someone help out? or explain?
1 answer:
Y = 90 degrees
1) The angles on a straight line add to 180 degrees so 180-110= 70 degrees.
2) The angles in a triangle add to 180 degrees so 70+70= 140 degrees. The angle at the top of the triangle will have to be 40 degrees as 140+40= 180 degrees.
3) As x is half the angle at the top of the triangle (40 degrees), x will equal 20 degrees.
4) As the angles in a triangle add to 180 degrees 20+70=90 degrees 180-90=90 degrees.
5) Answer = 90 degrees
1) The angles on a straight line add to 180 degrees so 180-110= 70 degrees.
2) The angles in a triangle add to 180 degrees so 70+70= 140 degrees. The angle at the top of the triangle will have to be 40 degrees as 140+40= 180 degrees.
3) As x is half the angle at the top of the triangle (40 degrees), x will equal 20 degrees.
4) As the angles in a triangle add to 180 degrees 20+70=90 degrees 180-90=90 degrees.
5) Answer = 90 degrees
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Answer:
a.) Between 0.5 and 3 seconds.
Step-by-step explanation:
So I just went ahead and graphed this quadratic on Desmos so you could have an idea of what this looks like. A negative quadratic, and we're trying to find when the graph's y-values are greater than 26.
If you look at the graph, you can easily see that the quadratic crosses y = 26 at x-values 0.5 and 3. And, you can see that the quadratic's graph is actually above y = 26 between these two values, 0.5 and 3.
Because we know that the quadratic's graph models the projectile's motion, we can conclude that the projectile will also be above 26 feet between 0.5 and 3 seconds.
So, the answer is a.) between 0.5 and 3 seconds.
