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Nikitich [7]
3 years ago
12

If the area of a circle measures 25π cm2, what is the circumference of the circle in terms of π?

Mathematics
2 answers:
ss7ja [257]3 years ago
5 0
Two formulas here:

Area = πr²

Circumference = 2<span>πr

So first we solve for r from area:

25</span>π = πr²

25 = r²

r = 5

So we know that radius is 5 cm.

Now substitute r to 5 in circumference formula:

C = 2π(5) = 10π

Final answer: 10π cm

Hope this helps.
zhannawk [14.2K]3 years ago
5 0

Answer:

10\pi cm

Step-by-step explanation:

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Step-by-step explanation:

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7 0
2 years ago
Pls help if you only know the answer thanks! :)
Ksju [112]

Answer:

C-0.1

Step-by-step explanation:

0.1 is between -3.8 and 0.

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8 0
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BRAINLIEST AND 20 POINTS ANSWER ASAP PLZ
galben [10]
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7. The surface area of a cone is A = pi*r*sqrt(r^2 + H^2)

A = pi*(7)(sqrt(49 + 1849)
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13. The volume of the slab is V = HLW
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21. First, find the volume of the rectangular prism. V = HLW
V = (15 cm)(5 cm)(7 cm)
V = 525 cm^3

Next, find the volume of the pyramid. V = 1/3(BH), where H is the height of the pyramid and B is the area of the base of the pyramid. Note that B = (15 cm)(5 cm) = 75 cm^2

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Add the two volumes together, the total volume is 850 cm^3. The fourth answer is correct.

22. The volume of a square pyramid is V = 1/3(S^2)(H), where S is the side length and H is the height.

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Now that we know the volume of this pyramid, and that both pyramids have equal volume, we plugin our V to the equation for the volume.

2800 = (1/3)(84)(S^2)
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100 = S^2
<span> 10 in = S, so we have a side length of 10 in, and the first answer is correct. </span>
3 0
3 years ago
Twelve education students, in groups of four, are taking part in a student-teacher program. Mark cannot be in the first group be
aliya0001 [1]
The answer is 330. Or answer B
7 0
3 years ago
Read 2 more answers
Three consecutive odd integers are such that the square of the third integer is 1515 greater than greater than the sum of the sq
Ksju [112]
Let
x-----------> first <span>odd integer
x+2--------> second consecutive odd integer
x+4-------> third consecutive odd integer

we know that
(x+4)</span>²=15+x²+(x+2)²-------> x²+8x+16=15+x²+x²+4x+4
x²+8x+16=19+2x²+4x-------> x²-4x+3
x²-4x+3=0

using a graph tool----------> to calculate the quadratic equation
see the attached figure
the solution is
x=1
x=3

the answer is
the first odd integer x is 1
the  second consecutive odd integer x+2 is 3
the third consecutive odd integer x+4 is 5

7 0
3 years ago
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