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Shtirlitz [24]
3 years ago
6

The difference in the measures of two complementary angles is 12 degrees. find the measure of the angles?

Mathematics
2 answers:
8090 [49]3 years ago
6 0

If two angles are complementary, the sum of their measures is 90 degrees. Call one of the angles x. This means that its complement is 90 - x degrees. But the difference in their measures is 12 degrees.
AlladinOne [14]3 years ago
3 0

Answer:

51° and 39°

Step-by-step explanation:

Complementary angles are angles that add up to 90°

If we let one angle = x

Then the other angle is ( 90 - x)

Since the difference between the two angles is 12°

⇒ x - (90 - x) = 12

x - 90 + x = 12

2x -90 = 12

2x = 102

x = 102/2

x = 51°

So, one of the angle is 51°

The other angle = 90 - x = 90 - 51 = 39°

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PLSSS HELP IF YOU TURLY KNOW THISS
Leni [432]

Answer:

15

Step-by-step explanation:

Co-efficient = number multiplied by a variable

The only number multiplied by a variable is 15, therefore, it's the co-efficient.

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4 0
1 year ago
In the solution of the equation 5 + 3x = -2x + 9, 2 x is added to the equation first. which of the following should be done next
wariber [46]

Hi!

<h3>Let's do the first step (add 2x). </h3>

5 + 3x + 2x = -2x + 2x + 9

<em>5 + 5x = 9</em>

<h3>Our goal is to isolate x on one side, so the next step would be to subtract 5 (or add -5).</h3>

5 + -5 + 5x = 9 + -5

<u><em>5x = 4</em></u>

<h2>The answer is B. add -5</h2><h3><em>And if you want to finish solving, you would divide by 5 on both sides.</em></h3>

5x/5 = 4/5

x = 0.8

Hope this helps! :)

-Peredhel

4 0
3 years ago
Show work please.<br><br> solve system of equations using matrices.
nadya68 [22]

Answer:

(t, t -1, t)

Step-by-step explanation:

You have three unknowns but only 2 equations, so you can't really SOLVE this...you can get a solution with a variable still in it (I forget what this is called.  I think it refers to infinite many solutions).  Here's how it works:

Set up your matrix:

\left[\begin{array}{ccc}1&-2&1\\2&-1&-1\\\end{array}\right] \left[\begin{array}{ccc}2\\1\\\end{array}\right]

You want to change the number in position 21 (the 2 in the scond row) to a 0 so you have y and z left.  Do this by multiplying the top row by -2 then adding it to the second row to get that 2 to become a 0.  Multiplying in a -2 to the top row gives you:

\left[\begin{array}{ccc}-2&4&-2\\2&-1&-1\\\end{array}\right]\left[\begin{array}{ccc}-4\\1\\\end{array}\right]

Then add, keeping the first row the same and changing the second to reflect the addition:

\left[\begin{array}{ccc}-2&4&-2\\0&3&-3\\\end{array}\right] \left[\begin{array}{ccc}-4\\-3\\\end{array}\right]

The second equation is this now:

3y - 3z = -3.  Solving for y gives you y = z - 1.  Let's let z = t (some random real number that will make the system true.  Any number will work.  I'll show you at the end.  Just bear with me...)

lf z = t, and if y = z - 1, then y = t - 1.  So far we have that y = t - 1 and z = t.  Now we solve for x:

From the first equation in the original system,

x - 2y + z = 2.  Subbing in t - 1 for y and t for z:

x - 2(t - 1) + t = 2.  Simplify to get

x - 2t + 2 + t = 2  and  x - t = 0, and x = t.  So the solution set is (t, t - 1, t).  Picking a random value for t of, let's say 2, sub that in and make sure it works.  If:

x - 2y + z = 2, then t - 2(t - 1) + t = 2 becomes t - 2t + 2 + t = 2, and with t = 2, 2 - 2(2) + 2 + 2 = 2.    Check it:  2 - 4 + 4 = 2 and 2 = 2.  You could pick any value for t and it will work.

6 0
3 years ago
On one day, 4 chefs and 5 helpers earned $650.
Arlecino [84]
4c + 5h = 650 and

5c + 6h = 800 where c are chefs, h are helpers

Start by finding an expression for c

4c + 5h = 650
4c = 650 -5h
c = (650- 5h)/4

Then substitute that into the second equation and solve for a number value for h
5 (650-5h)/4 + 6h = 800
(3250-25h)/4 + 6h = 800
Multiply both sides by 4
3250-25h + 24h = 3200
-h = -50
h = 50

Take that 50 and substitute it into the expression we have for c to get a number value for c

C= 650-5(50)/4
C = 650-250/4
C = 400/4
C= 100

Check your first equations, substituting $50 for the helpers and $100 for the chefs.

4 (100) + 5(50) =
400 + 250 = 650

5(100) + 6(50) =
500 + 300 = 800
6 0
3 years ago
Please Help me for 18 points
maxonik [38]
B


It’s b
Have a good day
3 0
3 years ago
Read 2 more answers
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