There are 2 ways that spring to mind.
One is to use the definition of the derivative at a point:

In this case,
and
. Then

- - -
If you don't know about derivative yet (I would think you do, considering this is for a midterm in AP Calc, but I digress), the other way is to rely on algebraic manipulation. Multiply the numerator and denominator by the conjugate of the numerator to get

This is continuous at
, so the limit is the value of the expression at
:

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Answer:
60 miles
Step-by-step explanation:
Distance apart = 100
Rate of travel. :
Anthony = 12 mph
Cleopafda = 8 mph
Using the relation :
Speed = distance / time
Distance = speed * time
If they leave at the same time, travel time Can be represented as x
Anthony's distance + Cleopafda distance = total distance
12x +. 8x = 100
20x = 100
x = 5
Hence, they both traveled for 5 hours before meeting.
Distance covered by Anthony :
Speed * time
12 mph * 5h = 60 miles
Anthony must travel. For 60 miles.
Answer:
6(3-2)
Step-by-step explanation:
Find the GCF of both numbers. The GCF is 6. Write it as 6( - )
Then, divide both numbers by 6. 18 divided by 6 is 3 and 12 divided by 6 is 2. Fill in the blanks with 3 and 2. A=6(3-2)