Answer:
1519
Step-by-step explanation:
if wrong super sooryyyyy :(
adding the 2 equations eliminates x and gives:-
5y = 60
y = 12
Plug y = 12 into the first equation:-
2x + 3(12) = 40
2x = 40 - 36 = 4 so x = 2
Answer is x = 2 and y = 12.
Answer:
6xy(x+2y)
Step-by-step explanation:
6x²y+12xy²
The GCF between 6 and 12 is 6. Factor out 6.
= 6(x²y+2xy²)
The GCF between x² and x is x. Factor out x.
= 6x(xy+2y²)
The GCF between y and y² is y. Factor out y.
= 6xy(x+2y)
Therefore, the GCF of the expression is 6xy and the factored expression is 6xy(x+2y).
I hope this helps!
A cone always contain a right angle.
To solve for the volume of a cone, we need to get the radius of the cone and its height.
Volume of a cone = π r² h/3
radius is the line from the center of the circle of the cone going to the edge of the circle.
height is the measurement of the cone from its pointy tip going downward.
Assuming the radius of the cone is 3 in. and its height is 6 inches.
Volume of a cone = π * r² * h/3
V = 3.14 * (3in)² * 6in/3
V = 3.14 * 9in² * 2in
V = 56.52 in³
Here the time function is h(t) = [6 + 96t - 16t^2] feet.
The initial height of the ball is 6 feet. That's when t=0. h(0)=[6+0-0] ft = 6 ft.
At t=7 sec, h(t) = [6 + 96t - 16t^2] feet becomes
h(7 sec) = h(t) = [6 + 96(7) - 16(7)^2] feet This produces a large negative number (-106 ft), which in theory indicates that the ball has fallen to earth and burrowed 106 feet into the soil. Doesn't make sense.
Instead, let t=1 sec. Then h(1 sec) = h(t) = [6 + 96(1) - 16(1)^2] feet
=[6 + 96 -16] ft, or 86 ft.
One sec after the ball is thrown upward, it reaches a height of 86 feet. It continues to rise, slowing down, until it finally stops for an instant and then begins to fall towards earth.
