Rosana used linear combination to solve the system of equations shown. She did so by multiplying the second equation by a certai
n number to eliminate the y-terms. What number did Rosana multiply the second equation by? 
1 answer:
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Answer:
- use the HL postulate
- corresponding angles are congruent; corresponding sides are congruent
Step-by-step explanation:
See below for the marking.
a) Marking the right triangles per the given information, we see that the hypotenuses and one leg are congruent. We can use the HL postulate of congruence to conclude the triangles are congruent.
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b) ∆CPS ≅ ∆WPD, so the following parts are congruent:
- ∠C ≅ ∠W
- ∠P (in ∆CPS) ≅ ∠P (in ∆WPD) — these are vertical angles
- ∠S ≅ ∠D
- CP ≅ WP
- PS ≅ PD
- CS ≅ WD
Answer:
The longest braking distance one of these cars could have and still be in the bottom 1% is of 116.94 feet.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
The braking distances of a sample of cars are normally distributed, with a mean of 129 feet and a standard deviation of 5.18 feet.
This means that
What is the longest braking distance one of these cars could have and still be in the bottom 1%?
This is the 1st percentile, which is X when Z has a pvalue of 0.01, so X when Z = -2.327.
The longest braking distance one of these cars could have and still be in the bottom 1% is of 116.94 feet.