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nikklg [1K]
3 years ago
6

What value of a makes the equation true?

Mathematics
2 answers:
Andrej [43]3 years ago
7 0
The answer is a= 2/5 i took the quiz
blagie [28]3 years ago
4 0
<span>1.7a+0.3a=4/5
2a = 4/5
  a = 4/5 * 1/2
  a = 4/10
a = 2/5

answer
</span>  a = 2/5

updated

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Through (7,2); parallel to 3x-y=8.
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x=4 y=4

Step-by-step explanation:

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The table below represents a linear relationship. What is the slope of the line?
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Please help me and If your answer is wrong or not appropreat I will report it
arsen [322]

Answer:

972 x^16 y^24

Step-by-step explanation:

Simplify the following:

(-2 x^3 y^7)^2 (3 x^2 y^2)^5

Multiply each exponent in -2 x^3 y^7 by 2:

(-2)^2 x^(2×3) y^(2×7) (3 x^2 y^2)^5

2×7 = 14:

(-2)^2 x^(2×3) y^14 (3 x^2 y^2)^5

2×3 = 6:

(-2)^2 x^6 y^14 (3 x^2 y^2)^5

(-2)^2 = 4:

4 x^6 y^14 (3 x^2 y^2)^5

Multiply each exponent in 3 x^2 y^2 by 5:

4 x^6 y^14×3^5 x^(5×2) y^(5×2)

5×2 = 10:

4×3^5 x^6 y^14 x^(5×2) y^10

5×2 = 10:

4×3^5 x^6 y^14 x^10 y^10

3^5 = 3×3^4 = 3 (3^2)^2:

4×3 (3^2)^2 x^6 y^14 x^10 y^10

3^2 = 9:

4×3×9^2 x^6 y^14 x^10 y^10

9^2 = 81:

4×3×81 x^6 y^14 x^10 y^10

3×81 = 243:

4×243 x^6 y^14 x^10 y^10

4 x^6 y^14×243 x^10 y^10 = 4 x^(6 + 10) y^(14 + 10)×243:

4×243 x^(6 + 10) y^(14 + 10)

14 + 10 = 24:

4×243 x^(6 + 10) y^24

6 + 10 = 16:

4×243 x^16 y^24

4×243 = 972:

Answer: 972 x^16 y^24

8 0
2 years ago
Read 2 more answers
Emily Dickinson's poetry was rescued for posterity by
mote1985 [20]
I think it might be B. but im not sure.
7 0
3 years ago
Read 2 more answers
The width of a rectangle is 5 more than twice the length. If the perimeter of the rectangle is 190 meters ,what is the width of
slega [8]
P=2(l+w)

190=2[(2l+5)+l)
190=4l+10+2l
190=6l+10
180=6l
l=30

190=2(30+w)
190=60+2w
130=2w
w=65

The width of the rectangle is 65.
6 0
3 years ago
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