Answer:
Correct option: (a) 0.1452
Step-by-step explanation:
The new test designed for detecting TB is being analysed.
Denote the events as follows:
<em>D</em> = a person has the disease
<em>X</em> = the test is positive.
The information provided is:
Compute the probability that a person does not have the disease as follows:
The probability of a person not having the disease is 0.12.
Compute the probability that a randomly selected person is tested negative but does have the disease as follows:
![P(X^{c}\cap D)=P(X^{c}|D)P(D)\\=[1-P(X|D)]\times P(D)\\=[1-0.97]\times 0.88\\=0.03\times 0.88\\=0.0264](https://tex.z-dn.net/?f=P%28X%5E%7Bc%7D%5Ccap%20D%29%3DP%28X%5E%7Bc%7D%7CD%29P%28D%29%5C%5C%3D%5B1-P%28X%7CD%29%5D%5Ctimes%20P%28D%29%5C%5C%3D%5B1-0.97%5D%5Ctimes%200.88%5C%5C%3D0.03%5Ctimes%200.88%5C%5C%3D0.0264)
Compute the probability that a randomly selected person is tested negative but does not have the disease as follows:
![P(X^{c}\cap D^{c})=P(X^{c}|D^{c})P(D^{c})\\=[1-P(X|D)]\times{1- P(D)]\\=0.99\times 0.12\\=0.1188](https://tex.z-dn.net/?f=P%28X%5E%7Bc%7D%5Ccap%20D%5E%7Bc%7D%29%3DP%28X%5E%7Bc%7D%7CD%5E%7Bc%7D%29P%28D%5E%7Bc%7D%29%5C%5C%3D%5B1-P%28X%7CD%29%5D%5Ctimes%7B1-%20P%28D%29%5D%5C%5C%3D0.99%5Ctimes%200.12%5C%5C%3D0.1188)
Compute the probability that a randomly selected person is tested negative as follows:
Thus, the probability of the test indicating that the person does not have the disease is 0.1452.
218they are the annnns erv
A) yes
B) yes
C) no
For each of these, substitute the value of x in the ordered pair into x in the function.
For A, x = -5; -5<2, so the piece of the function we want is f(x) = 3. In our ordered pair, y=f(x)=3, so yes, it is a solution.
For B, x = 2; 2≤2<6, so the piece of the function we want is f(x) = -x+1. In our ordered pair, y=f(x)=-1; -2+1=-1, so yes, it is a solution.
For C, x = 8; 8≥6, so the piece of the function we want is f(x) = x. In our ordered pair, y=f(x)=-7; -7≠8, so no, it is not a solution.
Answer:
The variation in apparent gravitational acceleration (g) at different locations on Earth is caused by two things.The distance between the centers of mass of two objects affects the gravitational force between them, so the force of gravity on an object is smaller at the equator compared to the poles.
Step-by-step explanation:
You can locate<span> any </span>point on the coordinate plane<span> using an ordered pair of numbers.
e.i. (4,2) will be 4 units to the right and 2 units up on the coordinate plane.</span>
