<span>Ishaan is 21, Christopher is 7
No actual question given, but I will assume that the question is "How old are they?". If that's the case, we can create two equations. I'll use I for Ishaan's age and C for Christopher's. I will also assume that there's been some formatting issues here and for some reason, numbers are repeated 3 times without any spaces. So
"Ishaan is 3 times as old as Christopher"
I = 3C
"is also 14 years older than Christopher
I = C + 14
Since both equations are equal to each other, let's set them equal. So
3C = C + 14
2C = 14
C = 7
So Christopher is 7. And we can use the equation I = C + 14 to get Ishaan's age. So
I = C + 14
I = 7 + 14
I = 21</span>
I thought doubling everytime except for the number 19000 because if you do 250 × 2 = 500 so then you do 500×2=1000.
Answer:
Explanation:
The given addition exercise is:
The LCM of the denominator (5 and 3) = 15
Multiply 2/5 by 3/3
Multiply 1/3 by 5/5
The addition becomes
Therefore, we can fill in the vacant boxes as shown below:
Answer:
<u>Infotron should produce each day 13 hockey and 6 soccer games</u>
Step-by-step explanation:
x = Number of hockey games Infotron should produce
y = Number of soccer games Infotron should produce
Number of labor-hours for assembly = 2x + 3y
Number of labor-hours for testing = 2x + y
Now we can write our equations system, this way:
2x + 3y = 44
2x + y = 32
*********************
Expressing y in terms of x in the 2nd equation:
2x + y = 32
y = 32 - 2x
********************
Substituting y and solving for x in the 1st equation:
2x + 3y = 44
2x + 3 * ( 32 - 2x) = 44
2x + 96 - 6x = 44
-4x = 44 - 96
-4x = - 52
x = -52/-4
x = 13
*****************
Solving for y in the 2nd equation:
2x + y = 32
2 * 13 + y = 32
26 + y = 32
y = 32 - 26
y =<u> 6</u>
<u>Infotron should produce each day 13 hockey and 6 soccer games</u>
Answer:
rectagular
Step-by-step explanation:
