A student leaves a sidewalk corner walks 3.0 blocks north then walks 3.0 blocks west.what is the students displacement from the
1 answer:
Answer:
The students displacement is 3·√3 blocks, 45° North of West
Explanation:
From the question, we have;
The distance North in which the student walks = 3.0 blocks
The next walking distance West by the student = 3.0 blocks
The displacement of the student = The shortest distance between the student start and final point
By representing the motion of the student in vector format, we have;
Therefore the magnitude of d is given as follows;
The direction of the student = tan⁻¹(3/3) = 45° West of North
The students displacement = 3·√3 blocks, 45° North of West.
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Answer:
3.28 cm
Explanation:
To solve this problem, you need to know that a magnetic field B perpendicular to the movement of a proton that moves at a velocity v will cause a Force F experimented by the particle that is orthogonal to both the velocity and the magnetic Field. When a particle experiments a Force orthogonal to its velocity, the path it will follow will be circular. The radius of said circle can be calculated using the expression:
r =
Where m is the mass of the particle, v is its velocity, q is its charge and B is the magnitude of the magnetic field.
The mass and charge of a proton are:
m = 1.67 * 10^-27 kg
q = 1.6 * 10^-19 C
So, we get that the radius r will be:
r = = 0.0328 m, or 3.28 cm.
