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scoray [572]
3 years ago
7

Need 3 examples of unbalanced forces

Physics
2 answers:
enyata [817]3 years ago
5 0

a roller coaster going down the first drop.

jarptica [38.1K]3 years ago
4 0
1. pulling tug of war
2. monkey swinging from vine
3. arm wrestle
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How many types of crust are there? List the names and one detail about each type
valina [46]

Answer:

There are two different types of crust: thin oceanic crust that underlies the ocean basins, and thicker continental crust that underlies the continents. These two different types of crust are made up of different types of rock.

Explanation:

There ya go !

:) hoping this helped ya out

5 0
2 years ago
Nuclear Size and Mass. The radii of most nuclei is given by the equation: R = R. 0. A1/3. R: radius of the nucleus, A: mass numb
mina [271]
Answer:

sssss

Explanation:

Hope this helps you
3 0
3 years ago
Although it shouldn’t have happened, on a dive i fail to watch my spg and run out of air. if my buddy is close by, my best optio
leva [86]

Answer:

B ) Ascend using my buddy alternative air source / make an emergency Ascent

Explanation:

From the description it can be seen his buddy is close by of which he can easily use the alternative air source. Also we can see that he is closer to the water surface than his buddy, of which controlled emergency swimming ascent is highly favourable in this condition.

5 0
3 years ago
Read 2 more answers
Which is not an example of a force?
NNADVOKAT [17]

Answer:

possibly A?

Explanation:

just feels right man

7 0
2 years ago
A force, F1, of magnitude 2.0 N and directed due east is exerted on an object. A second force exerted on the object is F2 = 2.0
IgorLugansk [536]

Answer:

Magnitude of the force is

F_3 = 2.83

direction of the force is given as

\theta = 45 degree West of South

Explanation:

As we know that force is a vector quantity and in order to find the resultant of two or more forces we need to add them vectorialy

So here we have

\vec F_1 + \vec F_2 + \vec F_3 = 0

here we know that first force is of magnitude 2 N towards east

\vec F_1 = 2 \hat i N

second force is also of 2.0 N due North

\vec F_2 = 2 \hat j

now from above equation

2\hat i + 2\hat j + \vec F_3 = 0

\vec F_3 = -2\hat i - 2\hat j

so magnitude of the force is given as

F_3 = \sqrt{2^2 + 2^2}

F_3 = 2.83

direction of the force is given as

\theta = tan^{-1}\frac{F_y}{F_x}

\theta = tan^{-1}\frac{-2}{-2}

\theta = 45 degree West of South

3 0
2 years ago
Read 2 more answers
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