Answer:
The component of F along AB is equal to Fcos45
F = 520N
Component along AB = 520cos45
= 367.7N
This is done by rotating the diamonds such that AB is now taken as the x-axis. Then the force F is resolved along AB.
Explanation:
Use w=m*g value of g is 1.67m/s^2
Answer:
The magnitude of the force between the two parallel wires is 0.0111 N.
Explanation:
Given;
length of the two parallel wires, L = 42 m
distance between the two wires, r = 0.03 m
current in both wires, I₁, I₂ = 6.3 A
Therefore, the magnitude of the repulsive force between the two parallel wires is given by;

Therefore, the magnitude of the force between the two parallel wires is 0.0111 N.
Answer:
Explanation:
the object will not move as the force exerted is not sufficient enough to overcome its force of friction
Answer:
Explanation:
b) Gravity reduces the initial upward velocity to zero in a time of
t = v/g = 40/10 = 4 s
a) h = v₀t + ½gt² = 40(4) + ½(-10)4² = 80 m
or
v² = u² + 2as
h = (0² - 40²) / 2(-10) = 80 m