A+b+c=6, a=2c, b=a+c using a and b in the first equation gives you:
2c+a+c+c=6 now use a=2c again
2c+2c+c+c=6
6c=6
c=1, since a=2c
a=2, since b=a+c
b=3
So the number is 231.
We can often solve inequalities by adding or subtracting a number from both sides
, there can be 0 , 1 , or 2 solutions<span> to a quadratic equation, depending on whether the expression inside the square root sign, (b </span>2<span> - 4ac) , is positive, negative, or zero</span>
Answer:
see below
Step-by-step explanation:
1a) -5(1) + 11 = 6
1b) -5(-3) + 11 = 26
1c) -5(0) + 11 = 11
1d) -5(1.2) + 11 = 5
1e) f of x equals negative 5x plus eleven
Answer:
B.
Step-by-step explanation:
