Answer:
x=13,y=0
Step-by-step explanation:
We are given a system of equations
For equation 1,square all terms to reduce it
√x²+√y²=169
x+y=13
Make x the subject as required by the question to use substitution method
x=13-y
Plug x=13-y into eqn 2
3(13-y)+2y=39
39-3y+2y=39
39-y=39
y=39-39=0
Plug y=0 into equation 1
x+0=13
x=0
I think you would use the equation 2x+1+33+90=180
Solving the given inequality for d, we get...
6d + 15 < 50
6d + 15-15 < 50-15 <<-- subtract 15 from both sides
6d < 35
6d/6 < 35/6 <<--- divide both sides by 6
d < 5.83
Which means that d can be any of the values in this set: {0, 1, 2, 3, 4, 5}
The smallest d can be is 0. In this scenario, Jeremy pays the $15 registration but doesn't rent the camera at all
The largest d can be is 5. In this scenario, Jeremy rents the camera for 5 days
Any larger value of d is not allowed as it would make the total cost go over $50
Notice how I'm rounding down regardless how close 5.83 is to 6
Answer:
A=28.13 Sq Ft
Step-by-step explanation:
Given that the length of the garden = 4.5 ft
Breadth of the garden = 6.25 ft
Area is given by the formula
A=length x breadth
A=4.5 x 6.25 sq ft
A= 28.125 sq ft
Here if we round the area to the nearest hundredth, the area will be
A=28.13 Sq Ft
Write two equations with the given information:
1) x = 2y ( x is twice the value of y)
2) x + y = 42
Replace x in the second equation with the value of x in the first equation:
2y + y = 42
Simplify:
3y = 42
Divide both sides by 3:
y = 42 / 3
y = 14
Now we have the value for Y, solve for x by replacing y with 14:
x = 2y
x = 2(14)
x = 28
X = 28 and y = 14
