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dybincka [34]
3 years ago
13

A family sized container of ice cream holds 16 3/4 cups of ice cream and costs $31.50. A store serves 1 1/3 cups of the same ice

cream in a bowl and charges $3.70. Which costs more per cup and by how much ?
Answer Choices:
A. The bowl costs $1.82 more.
B. The family sized container costs $1.88 more per cup.
C.The bowl costs $0.90 more per cup.
D. The bowl costs $2.77 more per cup.

Mathematics
1 answer:
Tema [17]3 years ago
5 0
I hope this helps you

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A triangle has angles measuring 23 and 48 degrees. What is the measure of the third angle?
icang [17]

Answer:

109

Step-by-step explanation:

Hope this helped :)

6 0
2 years ago
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Find the equation of the line<br> passing through the points 1,-5)<br> and (9,11).<br> y = 2x + [?]
Naily [24]

Answer:

y = 2x - 7

Step-by-step explanation:

Looks like we already have the slope of this line:  It is 2.  Working with the point (1, -5), we have x = 1 and y = -5 and can from this info easily find the y-intercept, b:

y = mx + b becomes

y  = 2x + b, which in turn becomes

-5 = 2(1) + b, or

b = -7,

and so the desired equation is y = 2x - 7

3 0
3 years ago
If 28% of students in College are near-sighted, the probability that in a randomly chosen group of 20 College students, exactly
cluponka [151]

Answer: (D) 16%

Step-by-step explanation:

Binomial probability formula :-

P(x)=^nC_xp^x(1-p)^n-x, where n is the sample size , p is population proportion and P(x) is the probability of getting success in x trial.

Given : The proportion of students in College are near-sighted : p= 0.28

Sample size : n= 20

Then, the the probability that in a randomly chosen group of 20 College students, exactly 4 are near-sighted is given by :_

P(x=4)=^{20}C_4(0.28)^4(1-0.28)^{20-4}\\\\=\dfrac{20!}{4!16!}(0.28)^4(0.72)^{16}\\\\=0.155326604912\approx0.16\%

Hence, the probability that in a randomly chosen group of 20 College students, exactly 4 are near-sighted is closest to 16%.

7 0
3 years ago
If an open box has a square base and a volume of 115 in.3 and is constructed from a tin sheet, find the dimensions of the box, a
Karolina [17]
Let h = height of the box,
x = side length of the base.

Volume of the box is  V=x^{2} h = 115. 
So h = \frac{115}{ x^{2} }

Surface area of a box is S = 2(Width • Length + Length • Height + Height • Width).
So surface area of the box is
S = 2( x^{2}  + hx + hx)  \\ = 2 x^{2}  + 4hx  \\  = 2 x^{2}  + 4( \frac{115}{ x^{2} } )x
= 2 x^{2} + \frac{460}{x}
The surface are is supposed to be the minimum. So we'll need to find the first derivative of the surface area function and set it to zero.

S' = 4x- \frac{460}{ x^{2} }  = 0
4x = \frac{460}{ x^{2} }  \\  4x^{3} = 460  \\ x^{3} = 115  \\ x =  \sqrt[3]{115} = 4.86
Then h=  \frac{115}{4.86^{2}} = 4.87
So the box is 4.86 in. wide and 4.87 in. high. 

5 0
3 years ago
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What is the y-intercept of a line with the equation (y - 3) = 5(x + 2)?
Nookie1986 [14]
The y-intercept would be (0, 13)
7 0
2 years ago
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