Ask question

Ask question

All categories

Vera_Pavlovna [14]

3 years ago

8

40 - 2 to the second power•9+17 can you please show me how you got this answer and tell me what it is please I will mark brainie

st

2 answers:

ollegr [7]3 years ago

5 0

Use orders of operations.
$40 - {2}^{2} \times 9 + 17 \\ 40 - 4 \times 9 + 17 \\ 40 - 36 + 17 \\ 4 + 17 \\ = 21$

bazaltina [42]3 years ago

4 0

359 bc 40-2=38 x 9=342 +17 =359

You might be interested in

A collection of 30 coins consists of dimes and nickels. The total value is $1. 95How many dimes are there?

Nonamiya [84]

21 nickels and 9 dimes

8 0

3 years ago

Read 2 more answers

What is the volume of a regular pyramid having a base area of 24 inches and height of 6 inches

Anestetic [448]

Answer:

V= 48 in^2

Step-by-step explanation:

Formula

Since the base has a known area, we do not need the full volume formula. This formula is

<em>V = B * h / 3</em>

B is the area of the base and h is the height measured from the top of the pyramid to the base meeting the base at right angles.

Givens

B = 24 in^2

h = 6 in

Solution

V = B * h / 3

V = 24 * 6/3

V= 48 in^2

6 0

1 year ago

Read 2 more answers

How do you find square root of any number just give me a example

soldier1979 [14.2K]

25/5=5 5•5=25 there should be a button ur calculator too

5 0

3 years ago

Read 2 more answers

If my finger was about 3 inches long, about how many centimeters would it be?

liraira [26]

It would be 7.62 centimeters. Just multiply how many inches you have by 2.54, and you'll have your conversion.
~Silver

7 0

3 years ago

Read 2 more answers

The weight of people in a small town in Missouri is known to be normally distributed with a mean of 186 pounds and a standard de

OleMash [197]

Answer:

the probability that a random sample of 17 persons will exceed the weight limit of 3,417 pounds is 0.0166

Step-by-step explanation:

The summary of the given statistical data set are:

Sample Mean = 186

Standard deviation = 29

Maximum capacity 3,417 pounds or 17 persons.

sample size = 17

population mean =3417

The objective is to determine the probability that a random sample of 17 persons will exceed the weight limit of 3,417 pounds

In order to do that;

Let assume X to be the random variable that follows the normal distribution;

where;

Mean $\mu$ = 186 × 17 = 3162

Standard deviation = $29* \sqrt{17}$

Standard deviation = 119.57

$P(X>3417) = P(\dfrac{X - \mu}{\sigma}>\dfrac{X - \mu}{\sigma})$

$P(X>3417) = P(\dfrac{3417 - \mu}{\sigma}>\dfrac{3417 - 3162}{119.57})$

$P(X>3417) = P(Z>\dfrac{255}{119.57})$

$P(X>3417) = P(Z>2.133)$

$P(X>3417) =1- 0.9834$

$P(X>3417) =0.0166$

Therefore; the probability that a random sample of 17 persons will exceed the weight limit of 3,417 pounds is 0.0166

5 0

3 years ago